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olasank [31]
3 years ago
15

Please help me with this question and can u please do it on paper and take a pic of it. Thank You!

Mathematics
1 answer:
Likurg_2 [28]3 years ago
4 0

click on <em>p</em><em>i</em><em>c</em><em>s</em><em> </em><em><u>c</u></em><em><u>l</u></em><em><u>i</u></em><em><u>c</u></em><em><u>k</u></em><em><u> </u></em>on pics

GodBless c:

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P(x)=-4x-2<br> Find p(a-3)
Marta_Voda [28]
Answer : -4a+10

Substitute (a-3) for x
-4(a-3)-2
-4a+12-2
-4a+10 but can also be written as -2(2a-5)
7 0
3 years ago
(05.08A)Triangle ABC is transformed to similar triangle A′B′C′ below:
Romashka-Z-Leto [24]

Answer:

1st option is correct i.e., 1 over 2

Step-by-step explanation:

Given that Triangle ABC transformed to Triangle A'B'C'.

Coordinated of Triangle ABC are A(2,6) , B(2,4) and C(4,4)

Coordinated of Triangle A'B'C' are A'(1,3), B'(1,2) and C'(2,2)

Scale factor of Dilation is the no. of times coordinates of vertices of a figure increase or decrease.i.e.,

if A(a,b) ⇒ A'(c,d)

where, a.k=c & b.k=d then k is scale factor of dilation.

Value of k is same for all vertices.

For coordinates of A & A' ,we have 2.k=1\implies k=\frac{1}{2} \:\: and \:\: 6.k=3\implies k=\frac{1}{2}

For coordinates of B & B' ,we have 2.k=1\implies k=\frac{1}{2} \:\: and \:\: 4.k=2\implies k=\frac{1}{2}

For coordinates of C & C' ,we have 4.k=2\implies k=\frac{1}{2} \:\: and \:\: 4.k=2\implies k=\frac{1}{2}

Therefore, the scale factor of dilation is \:\frac{1}{2}\:  since in all cases k=\frac{1}{2}

1st option is correct i.e., 1 over 2

3 0
3 years ago
SomeOne Please help me answer this question.
saw5 [17]

Answer: 79 degrees

Step-by-step explanation:

4x+1 + 3x+4 = 180

7x + 5 = 180

7x = 175

x = 175:7 = 25

m8 = 3x + 4 = 3*25 + 4 = 79

3 0
3 years ago
Tracy found the length of GF. Her work is shown below.
Sveta_85 [38]

she used GF=2BG,but the statement is correct BG=2GF

3 0
3 years ago
Read 2 more answers
Need help! Not sure what exactly is going on here!
marishachu [46]

Answer:

idk

Step-by-step explanation:

4 0
3 years ago
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