Let x be the distance from Syracuse where they pass. The first car travels a distance of x in time x/65 while the second car travels a distance 240-x in time (240-x)/55. They pass at the same time after leaving their starting points so x/65=(240-x)/55.
Cross-multiplying we get: 55x=65(240-x)=15600-65x, 120x=15600, x=15600/120=130 miles.
They pass 130 miles from Syracuse.
Answer:
When the eqn cuts the x-axis , y=0
3x=12
x=12/3
x=4
So,at x=4 is the point at which the linear equation cuts the x-axis
Answer:
LE FALTA 50 gr
Step-by-step explanation:
PESCADO MEDIO KG= 500 gr
CARNE DE RES= 450 gr
500+450=950 gr
1000 - 950= 50 gr


- <u>We </u><u>have </u><u>given </u><u>that </u><u>the </u><u>coordinates </u><u>of </u><u>the </u><u>end </u><u>point </u><u>G </u><u>and </u><u>H </u><u>are </u><u>(</u><u> </u><u>-</u><u>6</u><u>,</u><u>5</u><u>)</u><u> </u><u>and </u><u>(</u><u> </u><u>2</u><u>,</u><u> </u><u>-</u><u>7</u><u> </u><u>)</u>

- <u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>length </u><u>of </u><u>GH </u>

The coordinates of G = ( -6 , 5 )
The coordinates of H = ( 2 , - 7 )
<u>According </u><u>to </u><u>the </u><u>distance </u><u>formula</u><u>, </u><u> </u><u>we </u><u>get </u><u>:</u><u>-</u><u> </u>

- <u>Here</u><u>, </u><u> </u><u>x1</u><u> </u><u>=</u><u> </u><u>-</u><u>6</u><u> </u><u>,</u><u> </u><u>x2</u><u> </u><u>=</u><u> </u><u>2</u><u> </u><u>and </u><u>y1</u><u> </u><u>=</u><u> </u><u>5</u><u> </u><u>,</u><u> </u><u>y2</u><u> </u><u>=</u><u> </u><u>-</u><u>7</u>
<u>Subsitute </u><u>the </u><u>required </u><u>values </u><u>in </u><u>the </u><u>above </u><u>formula </u>








You basically plug in the x in the equation, for example if x = 4 and the equation is y = 2x + 5 you plug in 4 and the equation becomes y = 2(4) + 5. you then multiply and get y=8+5. from here u just add it and u get ur answer