All categories

3 years ago

Solve using inequalities 6<k/9+7

Mathematics

1 answer:

valentinak56 [21]3 years ago

3 0

Answer:

Let's solve your problem step-by-step:

6 < k/9 +7

Step 1: Simplify both sides of the inequality:

6<1/9 k+7

Step 2: Flip the equation:

1/9 k+7 > 6

Step 3: Subtract 7 from both sides:

1/9 k+7 -7 > 6-7

1/9 k > - 1

Step 4: Multiply both sides by 9:

9 * (1/9) > (9) * (-1)

Answer: k > − 9

Step-by-step explanation:

Please mark me Brainliest!

Hope this helps! Good luck! :)

You might be interested in

Which of the following equations is equivalent to the equation 6x-y=1

kondaur [170]

A. 6x-y=1 can go to 6x-y-1=0 and then 6x-1 = y

3 0

4 years ago

Read 2 more answers

Solve the inequality 2x – 5 > 7 a. x>6 b. x >12 c. x

julsineya [31]

You start with 2x -5>7 the you add five to both sides 2x-5+5>7 +5 2x.12 then divide both sides by 2 2x divided by 2 > and 12 divided by 2 and get x>6

3 0

3 years ago

elena55 [62]

Answer:

C. 0.300 s.

11 + x

Step-by-step explanation:

brainest plz

4 0

3 years ago

Read 2 more answers

Marcus sorts his 85 baseball cards into stacks of 9 cards each.How many stacks of 9 cards can Marcus make?4th grade homework

laiz [17]

9 stacks of cards and 4 cards left over because when you divide 85 by 9 you get 9.4. So you'd multiply just 9 to get 81 and 4 cards leftover

7 0

3 years ago

Pyramid A and Pyramid B are similar. Pyramid A has a volume of 648 m and Pyramid B has a

ryzh [129]

Answer:

the ratio of the surface area of Pyramid A to Pyramid B is: $\frac{36}{49}$

Step-by-step explanation:

Given the information:

Pyramid A : 648 $m^{3}$
Pyramid B : 1,029 $m^{3}$
Pyramid A and Pyramid B are similar

As we know that:

If two solids are similar, then the ratio of their volumes is equal to the cube

of the ratio of their corresponding linear measures.

<=> $\frac{Volume of A }{Volume of B}$ = $(\frac{a}{b}) ^{3}$ = $\frac{684}{1029}$ = $\frac{216}{343}$

<=> $\frac{a}{b} =$ $\frac{6}{7}$

Howver, If two solids are similar, then the n ratio of their surface areas is equal to the square of the ratio of their corresponding linear measures

<=> $\frac{surface area of A}{surface area of B} =( \frac{a}{b}) ^{2}$

= $\frac{36}{49}$

So the ratio of the surface area of Pyramid A to Pyramid B is: $\frac{36}{49}$

7 0

3 years ago

Solve using inequalities 6<k/9+7​

Solve using inequalities 6<k/9+7