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scZoUnD [109]
3 years ago
14

What is the solution to the system of equations below? 5 x + 2y = -3 3x + 6y = 6

Mathematics
1 answer:
Orlov [11]3 years ago
3 0
Eqn (1)*3: 15x + 6y = -9 -> Eqn (3)
Eqn (3) - Eqn (2): 12x = -15
x = -5/4 = -1 1/4
Eqn (2): -15/4 + 6y = 6
6y = 9 3/4
y = 1 5/8

x = -1 1/4
y= 1 5/8
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Solve the following differential equations or initial value problems. In part (a), leave your answer in implicit form. For parts
shepuryov [24]

Answer:

(a) (y^5)/5 + y^4 = (t^3)/3 + 7t + C

(b) y = arctan(t(lnt - 1) + C)

(c) y = -1/ln|0.09(t + 1)²/t|

Step-by-step explanation:

(a) dy/dt = (t^2 + 7)/(y^4 - 4y^3)

Separate the variables

(y^4 - 4y^3)dy = (t^2 + 7)dt

Integrate both sides

(y^5)/5 + y^4 = (t^3)/3 + 7t + C

(b) dy/dt = (cos²y)lnt

Separate the variables

dy/cos²y = lnt dt

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y = arctan(t(lnt - 1) + C)

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(t² + t) dy/dt = ty² - y²

(t² + t) dy/dt = y²(t - 1)

(t² + t)/(t - 1)dy/dt = y²

Separating the variables

(t - 1)dt/(t² + t) = dy/y²

tdt/(t² + t) - dt/(t² + t) = dy/y²

dt/(t + 1) - dt/(t(t + 1)) = dy/y²

dt/(t + 1) - dt/t + dt/(t + 1) = dy/y²

Integrate both sides

ln(t + 1) - lnt + ln(t + 1) + lnC = -1/y

2ln(t + 1) - lnt + lnC = -1/y

ln|C(t + 1)²/t| = -1/y

y = -1/ln|C(t + 1)²/t|

Apply y(1) = -1

-1 = ln|C(1 + 1)²/1|

-1 = ln(4C)

4C = e^(-1)

C = (1/4)e^(-1) ≈ 0.09

y = -1/ln|0.09(t + 1)²/t|

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...
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Answer:

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The radius of a circle is 10. Using π, which equation expresses the ratio of the circumference of the circle to the circle's dia
aleksley [76]

The ratio of circumference to diameter is independent of the radius.



Defining C=circumference, r=radius, D=diameter =  2r



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scale of the drawing = original dimensions / dimensions of the scale drawing

7/28

Ans 1:4

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