Let <em>w</em> be the wind speed and <em>p</em> the plane's speed in still air.
Flying against the wind, the plane has velocity
<em>p</em> - <em>w</em> = 390 mi/h
and flying with it, it has
<em>p</em> + <em>w</em> = 470 mi/h
Add the two equations together to eliminate <em>w</em> and solve for <em>p</em> :
(<em>p</em> - <em>w</em>) + (<em>p</em> + <em>w</em>) = 390 mi/h + 470 mi/h
2<em>p</em> = 860 mi/h
<em>p</em> = 430 mi/h
Subtract them to eliminate <em>p</em> and solve for <em>w</em> :
(<em>p</em> - <em>w</em>) - (<em>p</em> + <em>w</em>) = 390 mi/h - 470 mi/h
-2<em>w</em> = -80 mi/h
<em>w</em> = 40 mi/h
In Euclidian geometry the sum of the interior angle measures of a triangle is 180 degrees, but in elliptical or spherical geometry the sum is greater than 180 degrees. As well as <span>In Euclidian geometry the sum of the interior angle measures of a triangle is 180 degrees, but in hyperbolic geometry the sum is less than 180 degrees. Are the answers.</span>
Answer:
Step-by-step explanation:
Area = area of rectangle 1 + area of rectangle 2 + area of rectangle 3 +area of triangle
= 8*12 + 12*9 + 19 *5 + (1/2) * 4 *12
= 96 + 108 + 95 + 24
= 323 sq. cm
Answer:
5:2 , 30:12 , 60:24 , etc.
Step-by-step explanation:
To identify ratios equivalent to 15:6, all you need to do is multiply or divide both numbers in the ratio by the same amount to find an equivalent ratio.
So, for example:
1:2 --> 1*2 : 2*2 = 2:4 Both one half, so equal.
Now for 15:6...
Let's divide by the least common denominator ( 3 )
15 / 3 and 6 / 3 = 5 and 2
So 15:6 = 5:2
And we can also multiply the ratio by any constant as well...
For example 15 * 2 and 6 * 2
So 30:12 = 15:6
Hope this helped!
Standard Form : ( x - 1 ) ^2 + ( y + 3 ) ^2 = 5
Center of the circle : ( 1 , -3 )
Radius: line mark over 5
