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2 years ago

What is equivalent to 5^3•5^4

Mathematics

1 answer:

mafiozo [28]2 years ago

8 0

Answer:

${5}^{7}$

Step-by-step explanation:

$5^3•5^4 = {5}^{3 + 4} = \purple{ \bold{ {5}^{7} }}$

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On a piece of paper, graph f(x)=16x0.5^x. Then determine which answer choice matches the graph you drew.

Reil [10]

9514 1404 393

Answer:

Step-by-step explanation:

You can use x=0 and x=1 to find points that must be on the graph.

f(0) = 16·0.5^0 = 16

f(1) = 16·0.5^1 = 8

Only graph A matches these points.

7 0

2 years ago

If you want to create a perfect curve, which tool would be most helpful?

luda_lava [24]

The most usfull tool would be a compas

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2 years ago

Read 2 more answers

Three populations have proportions 0.1, 0.3, and 0.5. We select random samples of the size n from these populations. Only two of

IRINA_888 [86]

Answer:

(1) A Normal approximation to binomial can be applied for population 1, if n = 100.

(2) A Normal approximation to binomial can be applied for population 2, if n = 100, 50 and 40.

(3) A Normal approximation to binomial can be applied for population 2, if n = 100, 50, 40 and 20.

Step-by-step explanation:

Consider a random variable X following a Binomial distribution with parameters n and p.

If the sample selected is too large and the probability of success is close to 0.50 a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

np ≥ 10
n(1 - p) ≥ 10

The three populations has the following proportions:

p₁ = 0.10

p₂ = 0.30

p₃ = 0.50

(1)

Check the Normal approximation conditions for population 1, for all the provided n as follows:

$n_{a}p_{1}=10\times 0.10=1$

Thus, a Normal approximation to binomial can be applied for population 1, if n = 100.

(2)

Check the Normal approximation conditions for population 2, for all the provided n as follows:

$n_{a}p_{1}=10\times 0.30=310\\\\n_{c}p_{1}=50\times 0.30=15>10\\\\n_{d}p_{1}=40\times 0.10=12>10\\\\n_{e}p_{1}=20\times 0.10=6$

Thus, a Normal approximation to binomial can be applied for population 2, if n = 100, 50 and 40.

(3)

Check the Normal approximation conditions for population 3, for all the provided n as follows:

$n_{a}p_{1}=10\times 0.50=510\\\\n_{c}p_{1}=50\times 0.50=25>10\\\\n_{d}p_{1}=40\times 0.50=20>10\\\\n_{e}p_{1}=20\times 0.10=10=10$

Thus, a Normal approximation to binomial can be applied for population 2, if n = 100, 50, 40 and 20.

8 0

2 years ago

Find the area of the shaded region

wariber [46]

31x^2 + 53x - 8

Use the FOIL method to find the area of the large rectangle. (7x - 2)(9 + 5x)

First term in each binomial: 7x * 9 = 63x
Outside terms: 7x * 5x = 35x^2
Inside terms: -2 * 9 = -18
Last term in each binomial: -2 * 5x = -10x

Now, just add them all up.

63x + 35x^2 - 8 - 10x

35x^2 + 53x - 8

Now find the area of the square.

2x * 2x = 4x^2

Now, subtract the areas.

31x^2 + 53x - 8

Please consider marking this answer as Brainliest to help me advance.

6 0

2 years ago

One pipe can fill a pool in 9 hours. Another pipe can fill the pool in 6 hours. How long would it take them to fill the pool if

kow [346]

Answer:

3.6 hours or 3 hours and 36 minutes.

Step-by-step explanation:

If the first pipe can fill the pool in 9 hours that means that in 1 hour it fills $\frac{1}{9}$ of the pool, we use the same logic for the second pipe and conclude that in 1 hour it feels up $\frac{1}{6}$ of the pool. If both were to fill the pool together that means that in 1 hour they would fill...

$\frac{1}{9} +\frac{1}{6} = \frac{5}{18}$ of the pool in 1 hour.

Now to find how many hours it will take divide the pool by the speed with which it is getting filled.

$1 / \frac{5}{18} = 3.6$ hours

3.6 hours in other words is 3 hours and 36 minutes.

3 0

2 years ago