Answer:
-5
Step-by-step explanation:
The dot means multiply: so 
Also: 5² = 5 x 5 = 25
Therefore,





Answer:
11984.18 dollars
Step-by-step explanation:
Given that an amount of 5700 dollars is invested at 11.2% p.a. for seven years compounded.
We have compound interest formula for Principal P for n years at r% compounded annually is
Final amount = 
Final amount for 5700 dollars at 11.2% p.a. for 7 years would be
11984.18 dollars.
Answer is 11984.18 dollars
Answer:
Step-by-step explanation:
Law of Sines recall Sin(A) /a = Sin(B) /b
does the above make sense?
Next we need to find the angle of A
notice that 16+75=91 :o
so angle A is only 89° ..(b/c all the way around then inside of a triangle is 180) so this is NOT a right triangle but that's okay, b/c law of sines still works fine.
then we want to find length of line AB
and if 89 = A then a = BC
and if 75 = B the b = AB (note that in the given triangle this is angle C, i'm using B , b/c you can see the difference between capital B and lower case b much easier than you can with C, & c :/ )
capitals are the angles while lower case are the length of the sides
then
Sin(89) / 29 = Sin(75) / b
solve the parts that can be put into numbers or solve for 'b' first, that means isolate 'b' all by itself on one side of the equal sign .
0.034477 = 0.965925/ b
b = 0.965925 / 0.034477
b = 28.0165
b = 28.0 ( to the nearest 10th)
we have the parts to plug in now
Sin(75) /
Answer:
x = 6
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
Step-by-step explanation:
<u>Step 1: Define Equation</u>
4x - 8 = 16
<u>Step 2: Solve for </u><em><u>x</u></em>
- Add 8 to both sides: 4x = 24
- Divide 4 on both sides: x = 6
<u>Step 3: Check</u>
<em>Plug in x into the original equation to verify it's a solution.</em>
- Substitute in <em>x</em>: 4(6) - 8 = 16
- Multiply: 24 - 8 = 16
- Subtract: 16 = 16
Here we see that 16 does indeed equal 16.
∴ x = 6 is the solution to the equation.