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kupik [55]
3 years ago
12

3x+2.2is equal to x=1.7

Mathematics
1 answer:
Leviafan [203]3 years ago
7 0

Answer:

7.3 answer

Step-by-step explanation:

x=1.7

now

3x+2.2

3×1.7+2.2

7.3

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Simplify<br>5/2y-1 - 6/3y-1​
Kipish [7]

Answer:

Step-by-step explanation:

First Group like terms:

5/2y-6/3y-1-1

Add similar elements:5/2y-6/3y=1/2y

1/2y-1-1

1/2y=y/2

=y/2-1-1

=y/2-2

6 0
2 years ago
P-please help (30 points)
liubo4ka [24]

Answer:

No .1

Ans ; 2

No.2

Ans ; 3

Step-by-step explanation:

Multiply or add and if the value is whole no. then its W else L

8 0
2 years ago
Graph the system of equations on your graph paper to answer the question.
scZoUnD [109]
<span>y=x-4
y=-x+6 
---------------------
Substitute x - 4 for y in </span>y=-x+6 
x-4=-x+6<span>
--------------------------------
Add X on each side
</span><span>x-4+x</span>=-<span>x+6+x
</span>2x - 4 = 6
--------------------------------------
Add 4 on each side
<span>2x-4+4</span>=<span>6+4
</span>2x = 10
------------------------------------------------
Divide by 2 on each side
2x ÷ 2 = 10 ÷ 2
x = 5
Now we have X
================================================================
To find Y we substitute 5 for x in y=<span>x-<span>4
</span></span>y = 5 - 4
y = 1
-----------------------------------------------------
Your answers are Y = 1 and X = 5

8 0
3 years ago
A piece of cardboard is 13 inches by 26 inches. A square is to be cut from each corner and the sides folded up to make an open-t
Vanyuwa [196]

Answer:

Hence the maximum possible volume will be the 778.53 c.c

Step-by-step explanation:

Given:

A rectangle with 13 x 26 dimensions

And corners are cut to form side squares.

To Find:

Maximum possible volume for box

Solution :

Consider a rectangle of 13 x 26 dimension with and side of square  at corner be x.

(Refer the attachment)

Now,

Formulating the volume equation for the box

So corner square sides we are going to fold up which makes height of the box

and remaining part will be length and breadth

As shown in fig,

Length=26-x

breadth=13-x

And height will be x

V(x)=x*(26-x)*(13-x)

To get maximum volume differentiate the above equation,

V(x)=x*(26*13-26*x-13*x+x^2)

V(x)=x^3-39x^2+338x\\

V'(x)=3x^2-78x+338

V''(x)=6x-78

Now ,Solve the Quadratic Equation to get x values,

3x^2-78x+338=0

x=[-b±(b^2-4ac)^1/2]/2a

x=[78±Sqrt[(78)^2-4*338*3)]/2*3

x=[78±Sqrt(3028)]/6

x=[78±55.027]/6

x=78+55.027/6 or x=78-55.027/6

x=22.17  or x=3.8288

Use these values in 6x-78 to know which value posses the max and min value for the function.

So when x=22.17

6x-78=6*22.17-78

=55.02>0  i.e function will have minimum value .

When x=3.8288

6*3.8288-78

=-55.0272<0 i.e. Function will have maximum value

Now, the function will defines the maximum volume

V(x)=x^3-39x^2+338x

V(x)=3.8288^3-39*(3.82883)^2+338*3.8288

V(x)=56.13-571.73+1294.13

V(x)=778.53 C.C

6 0
3 years ago
Two sides of a triangle measure 10cm and 18cm . Which could be the measure of the third side of the triangle?
ValentinkaMS [17]
It cannot be 30, because the sum of two sides should be more than third side
-not D
10+18=28 <30

it cannot be 6 +10 < 18

it cannot 8
8+10=18

so it is has to be C) 12
12+18>10
10+12>18
10+18>12
answer  C. 12 cm

8 0
3 years ago
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