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3 years ago

Please helpp middle school mathsuppose 4<a<7. find all the possible values of 15-2a

Mathematics

1 answer:

bixtya [17]3 years ago

8 0

9514 1404 393

Answer:

1 < 15 -2a < 7

Step-by-step explanation:

There are a couple of ways you can do this.

1) Put the minimum and maximum values of a into the expression to see what its corresponding values are:

15-2a for a=4:

15-2(4) = 7

15-2a for a=7:

15-2(7) = 1

Then ...

1 < 15-2a < 7

2) Solve for a in terms of the value of 15-2a, then impose the limits on a.

x = 15 -2a

2a = 15 -x

a = (15 -x)/2

Now, impose the given limits:

4 < (15 -x)/2 < 7

8 < 15 -x < 14 . . . multiply by 2

-7 < -x < -1 . . . . . . subtract 15

7 > x > 1 . . . . . . . . multiply by -1

1 < 15-2a < 7 . . . . . use x=15-2a

_____

The vertical extent of the attached graph is the range of possible values of 15-2a. It goes from 1 to 7.

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franklin school has 3 boys for every 4 girls in the fifth grade. there are 140 students in the 5th grade. How many boys are ther

marin [14]

Answer:

There are 60 boys and 80 girls in Franklin School.

Step-by-step explanation:

"franklin school has 3 boys for every 4 girls in the fifth grade." means that the ratio of boys to girls is: 3:4

It can also be written as 3/4

Also given

Total number of students: 140

We will use ratios to find the number of boys and girls in shool.

First of all, we have to calculate the sum of ratio which is: 3+4 = 7

Let b be the number of boys and g be the number of girls

Then

$b = \frac{Ratio\ of\ boys}{Sum\ of\ ratio} * Total\ students\\= \frac{3}{7} * 140\\= 3*20\\=60\\g = \frac{Ratio\ of\ girls}{Sum\ of\ ratio} * Total\ students\\g = \frac{4}{7}*140\\= 4*20\\=80$

Hence,

There are 60 boys and 80 girls in Franklin School.

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2 years ago

Find the coordinates of a point that divides the directed line segment PQ in the ratio 5:3. A) (2, 2) B) (4, 1) C) (–6, 6) D) (4

Yuri [45]

Answer:

The answer is explained below

Step-by-step explanation:

The question is not complete we need point P and point Q.

let us assume P is at (3,1) and Q is at (-2,4)

To find the coordinate of the point that divides a line segment PQ with point P at $(x_1,y_1)$ and point Q at $(x_2,y_2)$ in the proportion a:b, we use the formula:

$x-coordinate:\\\frac{a}{a+b}(x_2-x_1)+x_1 \\\\While \ for\ y-coordinate:\\\frac{a}{a+b}(y_2-y_1)+y_1$

line segment PQ is divided in the ratio 5:3 let us assume P is at (3,1) and Q is at (-2,4). Therefore:

$x-coordinate:\\\frac{5}{5+3}(-2-3)+3 \\\\While \ for\ y-coordinate:\\\frac{5}{5+3}(4-1)+1$

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3 years ago

In the right triangle above a=2.7 and b=4.3. Find the value of c, rounded to the nearest tenth

morpeh [17]

Answer:

5.1

Step-by-step explanation:

Since there is no diagram provided here, we assume that c is the length of the hypotenuse, so we have ...

c² = a² +b² . . . . . . Pythagorean theorem

c² = 2.7² +4.3² = 25.78

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3 years ago

A person can read 48 pages in 5/4 of an hour. How many pages can they read in one hour

erma4kov [3.2K]

Answer:

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Step-by-step explanation:

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8 0

3 years ago

Help pls ASAP!!!!!!!!

eduard

Answer:

Option 1 and 2

Step-by-step explanation:

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6 0

3 years ago

Please helpp middle school mathsuppose 4<a<7. find all the possible values of 15-2a​

Please helpp middle school mathsuppose 4<a<7. find all the possible values of 15-2a