ANSWER

EXPLANATION
The given expression is

We factor to get,

This implies that,

We factor further to obtain,

or
59$ mangotes
Ánd un aplle
Hello :
<span>(27ax^3 – 9a^2x) ÷ 3ax :
</span> <span>(27ax^3 – 9a^2x) / 3ax
</span> (27ax^3 ) / (3ax) –( 9a^2x) / 3ax = 9x² - 3a
Answer:
The reasonable measurement in question 1 is D - the distance from New York to California is 2,250 miles. The best unit of measurement for the length of the distance of your textbook is A - inch.
Step-by-step explanation:
The United States uses the Imperial System of measurement which uses things such as inches, feet, yards and miles. In order to understand reasonable measurements, you need to first realize the order in which size would be determined. For instance, 12 inches is equal to one foot, which can be found on your typical ruler. Additionally, three feet is equal to one yard, which we can find on a yard stick. Lastly, there are 1,760 yards in one mile, which is typically measured with some time of pedometer/odometer. So, when you think about calculating measurement for common things such as a pencil or distance between cities, think about whether this distance could be measured using a ruler or perhaps the odometer on a car.
Answer:
(a)18
(b)1089
(c)Sunday
Step-by-step explanation:
The problem presented is an arithmetic sequence where:
- First Sunday, a=1
- Common Difference (Every subsequent Sunday), d=7
We want to determine the number of Sundays in the 120 days before Christmas.
(a)In an arithmetic sequence:

Since the result is a whole number, there are 18 Sundays in which Aldsworth advertises.
Therefore, Aldsworth advertised 18 times.
(b)Next, we want to determine the sum of the first 18 terms of the sequence
1,8,15,...

The sum of the numbers of days published in all the advertisements is 1089.
(c)SInce the 120th day is the 18th Sunday, Christmas is on Sunday.