The answer is definitely a
Answer:
because they inject it into the animals eye's
Use the rules of logarithms and the rules of exponents.
... ln(ab) = ln(a) + ln(b)
... e^ln(a) = a
... (a^b)·(a^c) = a^(b+c)
_____
1) Use the second rule and take the antilog.
... e^ln(x) = x = e^(5.6 + ln(7.5))
... x = (e^5.6)·(e^ln(7.5)) . . . . . . use the rule of exponents
... x = 7.5·e^5.6 . . . . . . . . . . . . use the second rule of logarithms
... x ≈ 2028.2 . . . . . . . . . . . . . use your calculator (could do this after the 1st step)
2) Similar to the previous problem, except base-10 logs are involved.
... x = 10^(5.6 -log(7.5)) . . . . . take the antilog. Could evaluate now.
... = (1/7.5)·10^5.6 . . . . . . . . . . of course, 10^(-log(7.5)) = 7.5^-1 = 1/7.5
... x ≈ 53,080.96
10*a = 10000000
a = 1000000, one million
5*10*b = 500000000
b = 10000000, ten million
About ten times.
Answer:
3x^3+ 12x^2-15x
Step-by-step explanation:
First, you would have to distribute the 3x to everything in the parentheses. So you can write it out as (3x*x^2)+(3x*4x)+(3x*5). Solving this will give you the answer. We'll start off with (3x*x^2). Because we are MULTIPLYING, this part will equal to 3x^3. There is ONE x with 3x (think of it as 3x^1) and 2 x's in x^2, having a total of 3 x's, or x^3. Since the 3 is being multiplied as well, we can write it as 3x^3.
Second, we will solve (3x*4x). We are multiplying, so first we multiply 3*4 and then x*x. 3*4 is 12 and x*x is x^2. There are 2 x's being mutipled by each other, so the x becomes squared. Now we finish and multiply 12*x^2 wich is 12x^2.
Lastly, we solve (3x*5). 3x is being multiplied 5 times which gives us 15x.
I hope this helped :)
