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3 years ago

Find the missing number in the pythagoras triplet. 9,12,___

Mathematics

1 answer:

CaHeK987 [17]3 years ago

6 0

15

add 3 to 9 and it’s 15

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Hey everyone. Can you help me out a bit? Willing to give brainliest. Image attached.

iren [92.7K]

The volume of the cylinder will be 40.69x ft².

<h3>How to calculate the volume?</h3>

It should be noted the volume of a cylinder will be calculated by using the formula:

= πr²h

In this case, it should be noted that the height of give as x and the diameter is 7.2

The volume will be:

= πr²h

= 3.14 × (7.2/2)² × x

= 40.69x ft²

Therefore, the volume of the cylinder will be 40.69x ft².

Learn more about volume on:

brainly.com/question/463363

#SPJ1

8 0

2 years ago

A diver descends to a location of -50 1 over 4 meters relative to the surface of the water. He then descends another 10 1 over 2

Yanka [14]

Answer:

$-60\frac{3}{4}$ meters.

Step-by-step explanation:

To find diver's final location relative to the surface of water we will subtract $10\frac{1}{2}$ from $-50\frac{1}{4}$ because diver dives away another $10\frac{1}{2}$ from his previous location of $-50\frac{1}{4}$ .

$-50\frac{1}{4} -10\frac{1}{2}$

Now we will convert our mixed fraction into improper fraction and then we will find a common denominator.

$\frac{-201}{4} -\frac{21}{2} =\frac{-201-42}{4}$

$=\frac{-243}{4}$

Now let us convert our answer in mixed fraction.

$=\frac{-243}{4}=[tex]-60\frac{3}{4}$ [/tex]

Therefore, diver's final location relative to the surface of the water is $-60\frac{3}{4}$ meters.

3 0

4 years ago

Read 2 more answers

Is -604.8 the right answer? (#2)

GrogVix [38]

<span>Is -604.8 the right answer I checked it </span>

6 0

3 years ago

3-i/1+i please answer in a +bi form

skad [1K]

Now... let's multiply the denominator and numerator by the conjugate of the denominator as already suggested, which is just the same, but with a different sign in the middle, 1 - i.

$\bf \textit{difference of squares}
\\ \quad \\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)
\\\\\\
\textit{also recall that }\qquad i^2=(\sqrt{-1})(\sqrt{-1})\implies i^2=-1\\\\
-------------------------------\\\\$

$\bf \cfrac{3-i}{1+i}\cdot \cfrac{1-i}{1-i}\implies \cfrac{(3-i)(1-i)}{(1+i)(1-i)}\implies \cfrac{(3-i)(1-i)}{(1^2)-(i^2)}
\\\\\\
\cfrac{3-3i-i+i^2}{1^2-(-1)}\implies \cfrac{3-3i-i+(-1)}{1+1}\implies \cfrac{3-1-3i-i}{2}
\\\\\\
\cfrac{2-4i}{2}\implies \cfrac{\underline{2}(1-2i)}{\underline{2}}\implies 1-2i$

8 0

3 years ago

(3x^2-2x+1) + (x^2 + 4x -3)

trasher [3.6K]

(3x^2-2x+1) + (x^2 + 4x -3)

Answer:

4x^2+2x-2

Explanation:

(3x^2+x^2) and (-2x+4x) and (1+-3)

4x^2 2x -2

8 0

3 years ago