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3 years ago

Please help me with any of these questions

Mathematics

1 answer:

Anuta_ua [19.1K]3 years ago

3 0

Answer:

10.-8/-2 can't represent calculating a mean change in score because a mean change in score is counted by adding up the scores & then dividing it by the number of the scores. As a number of scores can never be negative, so -8 can't be divided by -2 . So, -8/-2 can't represent this.

6. a) Andrea's mean weekly change will be negative. Because after adding up her weekly changes, we'll find a negative number. & as the number of weeks is positive, then the mean will be a negative number .

b)the division equation is: -15/5

So, her mean weekly change is -3

Step-by-step explanation:

I know it's late, but I hope it helps

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4 years ago

Will give brainiest and thx for the help

irinina [24]

C would be the correct answer I hope you have an amazing day!

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3 years ago

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mina [271]

Answer:

The mean will change, the median will stay the same.

Step-by-step explanation:

The mean will increase because that is the average and a gain of 1000 kg will increase that average.

The median will not change. The median is the middle point. That was the highest point before and increasing it will not change that it was the highest point.

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3 years ago

Read 2 more answers

Twenty people in your class want to be on a 5-person bowling team to represent the

arlik [135]

Answer:

4 :)

Step-by-step explanation:

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3 years ago

Item2

STatiana [176]

Answer:

Kindly check explanation

Step-by-step explanation:

Sample 1 :

Mean = (79.2 + 78.8 + 80 + 78.4 + 81) / 5 = 79.48

Range = 81 - 78.4 = 2.6

Sample 2 :

Mean = (80.5 + 78.7 + 81 + 80.4 + 80.1) / 5 = 80.14

Range = 81 - 78.7 = 2.3

Sample 3 :

Mean = (79.6 + 79.6 + 80.4 + 80.3 + 80.8) / 5 = 80.14

Range = 80.8 - 79.6 = 1.2

Sample 4 :

Mean =(78.9 + 79.4 + 79.7 + 79.4 + 80.6)/5 = 79.6

Range = 80.6 - 78.9 = 1.7

Sample 5 :

Mean = (80.5 + 79.6 + 80.4 + 80.8 + 78.8)/5 = 80.02

Range = 80.8 - 78.8 = 2

Sample 6 :

Mean =(79.7 + 80.6 + 80.5 + 80 + 81.1)/5 = 80.38

Range = 81.1 - 79.7 = 1.4

Xbar = mean of the means

Xbar = (79.48+80.14+80.14+79.6+80.02+80.38) / 6 = 79.96

Rbar = Mean of the sample ranges

Rbar = (2.6 + 2.3 + 1.2 + 1.7 + 2 + 1.4) / 6 = 1.87

n =5 ;D4 = 2.11 ; D3 = 0

From table, D4 = 2.11 ; D3 = 0

Range chart :

Upper Control limit, UCL = D4 * Rbar ; 2.11*1.87 = 3.9457 = 3.95

Lower Control limit, LCL = D3 * Rbar ; 0*1.87 = 0

Mean chart :

Xbar ± A2 * Rbar

From the table :

n = 5 ; A2 = 0.58

Lower control limit(LCL) = Xbar - A2*Rbar

LCL = 79.96 - (0.58*1.87) = 78.8754 = 78.88

Upper Control Limit (UCL) = Xbar + A2*Rbar

UCL = 79.96 + (0.58*1.87) = 81.0446 = 81.04

(78.88 ; 81.04)

The value of Each sample mean falls within the mean interval, Hence, We can conclude that process is on control.

7 0

3 years ago