Answer:
Answer:
safe speed for the larger radius track u= √2 v
Explanation:
The sum of the forces on either side is the same, the only difference is the radius of curvature and speed.
Also given that r_1= smaller radius
r_2= larger radius curve
r_2= 2r_1..............i
let u be the speed of larger radius curve
now, \sum F = \frac{mv^2}{r_1} =\frac{mu^2}{r_2}∑F=
r
1
mv
2
=
r
2
mu
2
................ii
form i and ii we can write
v^2= \frac{1}{2} u^2v
2
=
2
1
u
2
⇒u= √2 v
therefore, safe speed for the larger radius track u= √2 v
Hey!
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Solution:
(5/4 = 1 1/4) and (1 1/4 + 6 = 6 1/4)
= 7 3/4 - 6 1/4 (5/4 = 1 1/4)
= 1 2/4 or 1 1/2
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Answer:
1 2/4 or 1 1/2
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Hope This Helped! Good Luck!
ooh nice answer bud Answer:
Step-by-step explanation:
Answer:
Step-by-step explanation:
<span>7<span><span>x/2</span>+10</span></span><span> So this is how it looks like?</span>
