How many different books did the children read

Mary is the manager of a new clothing shop. The shop located in a new shopping mall and Mary wants to estimate the average daily

sergeinik [125]

Explanation:

a) First, note that the Type I error refers to a situation where the null hypothesis is rejected when it is actually true. Hence, her null hypothesis would be H0: mean daily demand of her clothes in this region should be greater than or equal to 100.

The implication of Type I error in this case is that Mary rejects that the mean daily demand of her clothes in this region is greater than or equal to 100 when it is actually true.

b) While, the Type II error, in this case, is a situation where Mary accepts the null hypothesis when it is actually false. That is, Mary accepts that the mean daily demand of her clothes in this region is greater than or equal to 100 when it is actually false.

c) The Type I error would be important to Mary because it shows that she'll be having a greater demand (which = more sales) for her products despite erroneously thinking otherwise.

5 0

4 years ago

in one year Orlando receive 62.51 inches of rain in September the city received 25% of that rainfall about how much rain did Orl

Angelina_Jolie [31]

Answer: 15.6275 inches of rain in September in Orlando.

How-To: percentages can be changed into decimals, by dividing 100. 25%/100=.25
The decimal .25=25%
So take 62.51 and multiply it by .25 and you get 15.6275

5 0

4 years ago

Write the equation for the perpendicular bisector of the given line segment.

Anon25 [30]

Answer:

$y=\frac{1}{3}x+\frac{5}{3}$