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Vedmedyk [2.9K]
3 years ago
15

Determine the value of x in the figure

Mathematics
1 answer:
goblinko [34]3 years ago
4 0
I think it’s B x = 137
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Jkl is an equilateral triangle jk= 13x+5,KL= 17X-19 AND JL= 8X+35​
stira [4]

Answer:

x = 6

Step-by-step explanation:

Since the triangle is equilateral then sides are congruent.

Equate any 2 sides and solve for x

13x + 5 = 8x + 35 ( subtract 8x from both sides )

5x + 5 = 35 ( subtract 5 from both sides )

5x = 30 ( divide both sides by 5 )

x = 6

JK = (13 × 6) + 5 = 78 + 5 = 83

KL = (17 × 6) - 19 = 102 - 19 = 83

JL = (8 × 6) + 35 = 48 + 35 = 83

ΔJKL is equilateral with side = 83

4 0
3 years ago
Heeeeelp Find the distance of AB if A (2, 6) and B (-5, 2).
evablogger [386]

Answer:

let A (2, 6) be (x1, y1)

B (-5, 2)  be (x2, y2)

distance AB =√[(x2 - x1)² + (y2 - y1)²]

                    √[(-7)²+ (-4)²]

                   √65

                   

7 0
3 years ago
How do you rotate the coordinate (9,-6) 270 degrees counterclockwise?
GalinKa [24]
Since this point is located in the fourth quadrant you have to rotate it 270 degrees counterclockwise which would end up being in third quadrant. which means the new point would be (-6,-9)
6 0
3 years ago
The length of a rectangle is 3 inches more than its width.
BlackZzzverrR [31]

Answer:

X=15

Step-by-step explanation:

Ignore the increase for equasion. This is factored in but irellevent. Orignal x value is 13, but increases to 15, and orignal x value is not needed for this equasion. (its there to confuse you)

L+L+W+W=66.

(w+3) +(w+3) +w +w = 66

(4xw) + 3 +3= 66

4 x w = 66 -3 -3

4 x w =60

60/4= 15.

L= 15+ 3 =18

W = 15.

W + W + L + L

15 + 15 + 18 +18 =66

3 0
3 years ago
Find the value of x and simplify completely.
jok3333 [9.3K]

Answer:

<h2>x=9√10</h2>

Given: A right triangle in which an altitude is drawn from the right angle vertex to the hypotenuse.

To find: 'x' the larger leg of triangle

Solution,

Using let rule for similarity in right triangle:

\frac{leg}{part}  =  \frac{hypotenuse}{leg}  \\ or \:  \frac{x}{27}  =  \frac{3 + 27}{x}  \\ or \: x \times x = 27(3 + 27) \\ or \: x \times x = 81 + 729 \\ or \:  {x}^{2}  = 810 \\ or \:  {x}^{2}  = 81 \times 10 \\ or \:  {x}  =  \sqrt{81 \times 10}  \\ or \: x =  \sqrt{81}  \times  \sqrt{10}  \\ or \: x =  \sqrt{ {(9)}^{2} }  \times  \sqrt{10}  \\  \: x = 9 \sqrt{10}

Hope this helps...

Good luck on your assignment..

7 0
3 years ago
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