Determine the value of x in the figure

How do you write 996 as a fraction, mixed number, or whole number in simplest form?

sveticcg [70]

To convert a mixed number to its lowest form, one needs to change the mixed number into an improper fraction and then reduce this improper fraction to the lowest possible fraction. To do these conversions, one needs to perform a few calculations. One also has to understand the definitions of "mixed number," "improper fraction" and "proper fraction."

A proper fraction is a fraction that has a lower number in the numerator and a higher number in denominator, such as the fraction three-fourths. An improper fraction is the inverse of this, which entails the higher number in numerator and lower number in the denominator, like 5/3. A mixed number is a whole number with a fraction, such as 1 3/4.

To convert the mixed number 1 3/4, one has to multiply the denominator 4 by the whole number 1 that gives 4, add this 4 to the 3 in the numerator to get 7 and place 7 over the denominator to find the improper fraction 7/4. In this case, this is the lowest form for this mixed number. However, if the mixed number is 6 4/6, then this converts to the improper fraction 40/6. One can divide the numerator and denominator of 40/6 by 2 to find that 20/3 is the lowest form for the mixed number 6 4/6.To convert a mixed number to its lowest form, one needs to change the mixed number into an improper fraction and then reduce this improper fraction to the lowest possible fraction. To do these conversions, one needs to perform a few calculations. One also has to understand the definitions of "mixed number," "improper fraction" and "proper fraction."

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3 years ago

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What is trigonometry

Vlada [557]

Answer:

the branch of mathematics dealing with the relations of the sides and angles of triangles and with the relevant functions of any angles.

Step-by-step explanation:

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3 years ago

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Suppose you have the following information. 12% of all drivers do not have a valid driver’s license, 6% of all drivers have no i

lubasha [3.4K]

Answer:

e) 0.14

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a driver does not have a valid driver's license.

B is the probability that a driver does not have insurance.

We have that:

$A = a + (A \cap B)$

In which a is the probability that a driver does not have a valid driver's license but has insurance and $A \cap B$ is the probability that a driver does not have any of these things.

By the same logic, we have that:

$B = b + (A \cap B)$

We start finding these values from the intersection.

4% have neither

This means that $(A \cap B) = 0.04$

6% of all drivers have no insurance

This means that $B = 0.06$ . So

$B = b + (A \cap B)$

$0.06 = b + 0.04$

$b = 0.02$

12% of all drivers do not have a valid driver’s license

This means that $A = 0.12$

So

$A = a + (A \cap B)$

$0.12 = a + 0.04$

$a = 0.08$

The probability that a randomly selected driver either fails to have a valid license or fails to have insurance is about

$P = a + b + (A \cap B) = 0.08 + 0.02 + 0.04 = 0.14$

So the correct answer is:

e) 0.14

8 0

3 years ago

The reduce feature on a copy machine is set at 84%. The picture being copied is 4.5 inches wide. What will be the width of yhe r

snow_tiger [21]

Answer:

The answer is 3.825 inches, the reduced picture will be 84% of the size of the original

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3 years ago

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Let f (x) = 3x − 1 and ε > 0. Find a δ > 0 such that 0 < ∣x − 5∣ < δ implies ∣f (x) − 14∣ < ε. (Find the largest

s344n2d4d5 [400]

Answer:

This proves that f is continous at x=5.

Step-by-step explanation:

Taking f(x) = 3x-1 and $\varepsilon>0$ , we want to find a $\delta$ such that $|f(x)-14|$

At first, we will assume that this delta exists and we will try to figure out its value.

Suppose that $|x-5|$ . Then

$|f(x)-14| = |3x-1-14| = |3x-15|=|3(x-5)| = 3|x-5|< 3\delta$ .

Then, if $|x-5|$ , then $|f(x)-14|$ . So, in this case, if $3\delta \leq \varepsilon$ we get that $|f(x)-14|$ . The maximum value of delta is $\frac{\varepsilon}{3}$ .

By definition, this procedure proves that $\lim_{x\to 5}f(x) = 14$ . Note that f(5)=14, so this proves that f is continous at x=5.

3 0

3 years ago