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Galina-37 [17]
3 years ago
14

Mr. Dey took out Rs.5000 from his bank. He took 40 notes of 50 Rupees each and the remaining amount in 20 Rupees notes. How many

20 Rupees notes did he take? *
Mathematics
2 answers:
nignag [31]3 years ago
5 0

Answer:

150

Step-by-step explanation:

We know that he took out Rs.5000 from the bank and that he took 40 of the 50 Rupees notes. We have to subtract to find the amount he took in 20 Rupees notes and then divide by 20 to find the number. 40*50 = 2000 and 5000 - 2000 = 3000. After that, 3000/20 = 150, so that means that Mr. Dey took out 150 notes of 20 rupees.

MrRa [10]3 years ago
3 0

Answer:

150

Step-by-step explanation:

Start with Rs.5000.

40 notes of 50 Rupees each = 40 * Rs.50 = Rs.2000

Rs.5000 - Rs.2000 = Rs.3000

He took Rs.3000 in 20 Rupees notes.

Rs.3000/Rs.20 = 150

Answer: He took 150 20-Rupee notes

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Evgesh-ka [11]

Answer:

x=-3/7 and y=_23/7

Step-by-step explanation:

y=-4x-5 and y=3x-2

using comparison method

-4x-5=3x-2

-4x-3x=-2+5

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x=3/-7

substituting the value of x

y=3x-2

=3×(-3/7)-2

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6 0
3 years ago
Which of the following inequalities matches the graph? (1 point)
Aleksandr [31]

Answer: 2x + y < 7

Step-by-step explanation:

In the graph we can see that:

The line is a dashed line, and the shaded area is below the dashed line, then we will have something like:

y < a*x + b

We also can see that the slope of the line is negative, and that the y-intercept is +7

Then the inequality will be something like:

y < a*x + 7

Now we can see that the line passes through the points (0, 7) and (3, 1)

Then the slope will be:

a = (1 - 7)/(3 - 0) = -6/3 = -2

that is negative, as we already said.

Then we have:

y < -2*x + 7

we can rewrite this as:

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What is the distance between (4,2) and (-1,-3)
Sati [7]
<h2>Solving for the Distance between two Points</h2><h3>Answer:</h3>

5 \sqrt{2} or 7.071

<h3>Step-by-step explanation:</h3>

<em>Please refer to my answer from this Question to know more about distances between two points: <u>brainly.com/question/24629826</u></em>

Given:

(4,2)

(-1,-3)

Solving for the Distance:

\sqrt{(4-(-1))^2 +(2 -(-3))^2} \\ \sqrt{(4 +1)^2 +(2 +3)^2} \\ \sqrt{5^2 +5^2} \\ \sqrt{25 +25} \\ \sqrt{50} \\ \sqrt{25 \cdot 2} \\ 5 \sqrt{2}

<u>Note:</u>

5 \sqrt{2} \approx 7.071

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Answer: 8

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The anwser is c your welcome
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