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3 years ago

A triangle has side lengths of 34in. 28in. and 42in. Is the triangle acute, right or obtuse?

Mathematics

1 answer:

Paul [167]3 years ago

5 0

I believe the answer is acute. Hope this helps!!

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On Monday,it took Helen 3 hours to do a page of science homework exercises.The next day she did the same number of exercises in

Blababa [14]

Answer:

It's 3/2p!

Step-by-step explanation:

Because Helen do the same number of exercises on 2 days, the time to do and the average rate are inversely proportional!

So, if on Monday, Helen's average rate is p then on the next day, her average rate is:

p × 3 ÷ 2 = $\frac{3p}{2}$

=3/2p

Brainliest?

3 0

3 years ago

Consider the initial value problem:

Inessa [10]

Answer:

$\left \{ {{u'=v} \atop {v'=5v-6u-5\sin(2t)}} \right. \\u(0)=-5;u'(0)=2$

Step-by-step explanation:

The given initial value problem is;

$y''-5y'+6y=-5\sin(2t)---(1)\\y(0)=-5,y'(0)=2$

Let

$u(t)=y(t)----(2)\\v(t)=y'(t)----(3)$

Differentiating both sides of equation (1) with respect to $t$ , we obtain:

$u'(t)=y'(t)---(4)\\ \\\implies u'(t)=v(t)---(5)$

Differentiating both sides of equation (2) with respect to $t$ gives:

$v'(t)=y''(t)----(6)$

From equation (1),

$y''=5y'-6y-5\sin(2t)\\y''=5v(t)-6u(t)-5\sin(2t)\\\implies v'(t)=5v(t)-6u(t)-5\sin(2t)----(7)$

Putting t=0 into equation (2) yields

$u(0)=y(0)\\\implies u(0)=-5$

Also putting t=0 into equation (3)

$u'(0)=y'(0)\\u'(0)=2$

The system of first order equations is:

$\left \{ {{u'=v} \atop {v'=5v-6u-5\sin(2t)}} \right. \\u(0)=-5;u'(0)=2$

3 0

4 years ago

If y = x - 4, what is x if y = 7?

riadik2000 [5.3K]

The answer would be that the X=3

4 0

3 years ago

Need help on this one!! plz show process

diamong [38]

Sally is 6 and Tomas is 3 so

6 +(3×2)

and 6-3

6 0

3 years ago

Use the image above to write a conjecture about regular polygons and lines of symmetry

Tatiana [17]

To find conjecture about regular polygon, use the formula $\frac{360}{n}$

Where, n = number of sides of the regular polygone

1) Triangle
n =3
So, Conjecture of the triangle = $\frac{360}{3}$ = 120

2) Square
n =4
So, Conjecture of the square = $\frac{360}{4}$ = 90

3) Pentagone
n = 5
So, Conjecture of the pentagon = $\frac{360}{5}$ = 72

4) Hexagone
n = 6
So, Conjecture of the pentagon = $\frac{360}{6}$ = 60.

7 0

4 years ago

Read 2 more answers