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Setler79 [48]
3 years ago
13

An online store manager calculates that the store receives $8,647 in orders each hour of

Mathematics
2 answers:
Crazy boy [7]3 years ago
7 0

Answer:

This question is not complete. Can you add the rest?

otez555 [7]3 years ago
3 0

Answer:

$207,528 in one 24 hour day.

Step-by-step explanation:

Not sure if this is what you were asking but you were not very clear.

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Fiona must find the length indicated by the dotted line for the tiles she is installing. She knows that each polygon is a regula
katen-ka-za [31]

The answer is B. 3.75 in.

Good luck:)

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3 years ago
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Just type the numerical answer.<br> Find the measure of angle A.<br> x+55<br> 86°<br> x+51
emmainna [20.7K]

Answer: x=-6

Step-by-step explanation:

x+55+x+51+86=180

2x+106+86=180

2x+192=180

2x=-12

x=-6

4 0
1 year ago
Subtract 428,731- 175 ,842
bearhunter [10]
Your answer is 252,889
7 0
4 years ago
Verify which of the following are identities.
-Dominant- [34]

Answer:

Only the second equation is an identity

Step-by-step explanation:

$8 \frac{\tan^2(\theta)}{\sec(\theta)} \csc^2(\theta)=8 \csc(\theta)$

<u>Note that </u>

\tan^2(\theta)\csc^2(\theta)=\sec^2(\theta)

<u>You can confirm it: </u>

$\frac{\sin^2(\theta)}{\cos^2(\theta)}\cdot    \frac{1}{\sin^2(\theta)}= \frac{1}{cos^2(\theta)}= \sec^2(\theta)$

<u>Therefore</u>

$8 \frac{\sec^2(\theta)}{\sec(\theta)} =8 \csc(\theta)$

$8 \frac{\sec(\theta)}{1} =8 \csc(\theta)$

8\sec(\theta)=8\csc(\theta)

<h2>It is not an Identity</h2>

<u>Let's the second one</u>

$13 \frac{\tan^2(\theta)}{\sec(\theta)} \csc^2(\theta)=13\sec(\theta)$

In this case, we already performed the calculations, so it is true. It is an Identity.

3 0
3 years ago
Need help on these math questions. please and thank u
Svetach [21]

9514 1404 393

Answer:

  a) x = -3

  b) y = (28/27)x -27

Step-by-step explanation:

a) College street has a slope of 0, so is a horizontal line. 2nd Ave is perpendicular, so is a vertical line, described by an equation of the form ...

  x = constant

For 2nd Ave to intersect the point (-3, 1), the constant must match that x-coordinate. The equation is ...

  x = -3

__

b) Since Ace Rd is perpendicular to Davidson St, its slope will be the opposite reciprocal of the slope of Davidson St. The slope of Ace Rd is ...

  m = -1/(-27/28) = 28/27

Using the point-slope equation for a line, we can model Ace Rd as ...

  y -y1 = m(x -x1)

  y -1 = (28/27)(x -27)

  y = (28/27)x -27

4 0
3 years ago
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