(Algebra II) 11. d. & e.
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The starting value is 20,300, and the value is decreasing by 9.5% each year.
Because it decreases by 9.5% each year based on the previous amount, we use an exponential decay model.
A decrease by 9.5% corresponds to multiplying by 91.5% each year.
We write . We plug in 11 years for t.
$7,671.18
Because it decreases by 9.5% each year based on the previous amount, we use an exponential decay model.
A decrease by 9.5% corresponds to multiplying by 91.5% each year.
We write . We plug in 11 years for t.
$7,671.18