Answer:
Step-by-step explanation:
2x²-3xy-2y²-2x-11y-12
Write -3xy as a difference
2x²+xy-4xy-2y²-2x-11y-12
write -2x as a difference
2x²+xy-4xy-2y²+4x-6x-11y-12
Write -11y as a difference
2x²+xy-4xy-2y²+4x-6x-8y-3y-12
Factor out 2x from the expression
2x×(x-2y-3)+xy-2y²+4x-8y-3y-12
Factor out y from the expression
2x×(x-2y-3)+y×(x-2y-3)+4x-8y-12
Factor out 4 from the expression
2x×(x-2y-3)+y×(x-2y-3)+4(x-2y-3)
Factor out x-2y-3 from the expression
Answer: (x-2y-3)x(2x+y+4)
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<u>Corrected Question</u>
The solution to an inequality is represented by the number line. How can this same solution be written using set-builder notation? {x | x > }
Answer:

Step-by-step explanation:
Given an inequality whose solution is represented by the number line attached below.
We observe the following from the number line
There is an open circle at 3, therefore the solution set does not include 3. (We make use of > or < in cases like that)
The arrow is pointed towards the right. All points to the right of 3 are greater than 3, therefore:
The solution in the number line can be written using set-builder notation as:

Answer:
x = 8.45
Step-by-step explanation:
5.4 + 0.2x = 7.09
Subtract 5.4 from both sides to leave 0.2x alone
0.2x = 1.69
Divide by 0.2 on both sides to isolate x
x = 1.69/0.2
x = 8.45