Answer:
Thats the answer from american school
Step-by-step explanation:
To compute the value of investment in 5 years. We use compounded annually equation. And add 2000 Yearly to the compounded value
A = P * (1 + (r/n))^(n*t)
A<span> = total amount = Unknown</span>
P<span> = principal or amount of money deposited, = 2000 usd</span>
r<span> = annual interest rate = 2.25%</span>
n<span> = number of times compounded per year = 1</span>
t<span> = time in years = 5
</span>
Solution
Year1 : A1 = 2000 * (1 +(0.025/1))^(1*1) = 2045
Year2 : A2 = (2000+2045)*(1 +(0.025/1))^(1*1) = <span>4136.01
Year3 : A3 = (2000+</span>4136.01))*(1 +(0.025/1))^(1*1) = <span>6274.07
Year4 : A4 = </span>(2000+6274.07 ))*(1 +(0.025/1))^(1*1) = <span>8460.24
Year5 : A5 = </span>(2000+8460.24 ))*(1 +(0.025/1))^(1*1) = 1<span>0695.6 </span>
Is the answer 12.7? Im not positive.
Answer:
When we have a function f(x), the average rate of change in the interval (a, b) is:
In this case, we have the function:
f(x) = (x + 3)^2 - 2
(but we do not have the interval, and I couldn't find the complete question online)
So if for example, we have the interval (2, 4)
The average rate of change will be:
If instead, we want the rate of change in a differential dx around the value x, we need to differentiate the function (this is way more complex, so I will define some rules first).
Such that the rate of change, in this case, will be:
f'(x) = df/dx
For a function like:
g(x) = x^n + c
g'(x) = n*x^(n - 1)
And for:
h(x) = k( g(x))
h'(x) = k'(g(x))*g'(x)
So here we can write our function as:
f(x) = k(g(x)) = (x + 3)^2 - 2
where:
g(x) = x + 3
k(x) = x^2 - 2
Then:
f'(x) = 2*(x + 3)*1 = 2*x + 6
That is the rate of change as a function of x (but is not an "average" rate of change)
Based on the given situation, if x is number of kilograms of lobster, you can write the following expressions:
51 + 5x cost in the first restaurant
33 + 8x cost in the second restaurant
In order to determine the value of x which makes the cost the same in both restaurants, equal the previous expressions and solve for x:
51 + 5x = 33 + 8x subtract 33 both sides and 5x subtract both sides
51 - 33 = 8x - 5x simplify
18 = 3x divide by 3 both sides
18/3 = x
6 = x
x = 6
Hence, the weight of the lobster is 6 kg.
The cost of the dinner is:
51 + 5(6) = 51 + 30 = 81
Hence, the cost of the dinner is $81
