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Anastasy [175]
3 years ago
9

Kyle gave 2/7 of his money to his wife and spent 4/5 of the remainder. If he had $300 left, how much money did he have at first?

​
Mathematics
1 answer:
densk [106]3 years ago
6 0

Answer:

$5,250

Step-by-step explanation:

2/7x - [4/5(2/7x)] = 300

2/7x - 8/35x = 300

10/35x = 8/35x = 300

2/35x = 300

2x = 10500

x = 5250

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The value of the circumference of circle A with a diameter of 27 cm is three times the value of the area of circle B. What is th
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The answer is 3 cm.

Circle A's diameter is 27, right? However, circle A is 3 times the value of the area of B. Because of that, you need to do 27/3, the inverse, in order to get the diameter of circle B. 

Next, because radius is half of the diameter, you do 9 divided by 3 or 9 times 1/2.

7 0
3 years ago
What is the least common mutliple of 10 and 12?
GalinKa [24]

Answer:

2

Step-by-step explanation:

You can divide both of them by 2

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3 years ago
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What is the product of 4/5x5/7?
Lubov Fominskaja [6]
20/35
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6 0
3 years ago
Anna has made 30 chocolate chip cookies and 54 sugar cookies. She wants to put them in bags for her friends with the same number
NARA [144]

Answer:

Therefore the greatest number of cookies she can put each bag is 14.

Step-by-step explanation:

Given that Anna has made 30 chocolate chip cookies and 54 sugar cookies.

First we have to find out the number of fried or the number of bags.

So to find the number of bags, We need to find out the G.C.D of 30 and 54.

30=5×3×2

54=3×3×3×2

The common divisor of 30 and 54 is = 3×2 = 6

∴The  G.C.D of 30 and 54 is 6.

The number of bags is 6.

The number of chocolate cookies each bags is

=(The number of chocolate cookies÷ 6)

=30÷6

=5

The number of sugar cookies each bags is

=(The number of sugar cookies÷ 6)

=54÷6

=9

Therefore the greatest number of cookies she can put each bag is (5+9)=14.

5 0
3 years ago
Sarah kicked a ball in the air. The function
Aleksandr-060686 [28]

Answer: The ball hits the ground at 5 s

Step-by-step explanation:

The question seems incomplete and there is not enough data. However, we can work with the following function to understand this problem:

f=30 t- 6t^{2} (1)

Where f models the height of the ball in meters and t the time.

Now, let's find the time t when the ball Sara kicked hits the ground (this is when f=0 m):

0=30 t- 6t^{2} (2)

Rearranging the equation:

6t^{2}-30 t=0 (3)

Dividing both sides of the equation by 6:

t^{2}-5 t=0 (4)

This quadratic equation can be written in the form at^{2}+bt+c=0, and can be solved with the following formula:  

t=\frac{-b \pm \sqrt{b^{2}-4ac}}{2a} (5)  

Where:  

a=1  

b=-5  

c=0  

Substituting the known values:  

t=\frac{-(-5) \pm \sqrt{(-5)^{2}-4(1)(0)}}{2(1)} (6)  

Solving we have the following result:

t=5 s  This means the ball hit the ground 5 seconds after it was kicked by Sara.

6 0
3 years ago
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