For this case, the first thing we must do is find the scale factor.
For this, we use one of the dimensions. We will use the width of the photo.
We have then:
Then, we look for the value of the height of the new photo. To do this, we multiply the scale factor by the original dimension.
We have then:
Answer:
the new height will be:
d.168 inches
Answer:
2 1/6
Step-by-step explanation:
Answer:
-24.8 m/s
Step-by-step explanation:
Given:
y₀ = 60 m
y = 40 m
v₀ = 15 m/s
a = -9.8 m/s²
Find: v
There are three constant acceleration equations we can use:
y = y₀ + v₀ t + ½ at²
v = at + v₀
v² = v₀² + 2a(y − y₀)
We aren't given the time, so we need to use the third equation, which is independent of time:
v² = v₀² + 2a(y − y₀)
Plug in the values:
v² = (15 m/s)² + 2(-9.8 m/s²) (40 m − 60 m)
v² = 617 m²/s²
v ≈ ±24.8 m/s
Since the coin is on the way down, the velocity is negative. So v = -24.8 m/s.
Answer:
radius = 1/2 * diameter = 1/2 * 16 = 8 units
Step-by-step explanation:
a=16
r=3
48/16=3
144/16=3
6th term
=ar^(n-1)
= 16(3)^(6-1)
=3888
