Answer:
p² -16pq + 36q²
Step-by-step explanation:
Given
(- 
p + 6q)²
= (- p + 6q)(- p + 6q)
Each term in the second factor is multiplied by each term in the first factor, that is
- p(- p + 6q) + 6q(- p + 6q)
= p² - 8pq - 8pq + 36q² ← collect like terms
= p² - 16pq + 36q²
H=2f/m+1
subtract one from both sides
h-1=2f/m
multiply m to both sides
m*h-1=2f
divide 2 both sides
mh-1/2=F
(the whole left side of the equation is divided by 2 i just cant do it on the computer)
Hello once again!
When you see a question like this, you need to find the equation of the straight line.
The formular used is y = mx + c
Where
m = slope
c = constant
First find the slope, since it's a straight line, any 2 coordinates can be used.
Now we need to substitude in the slope, and one of the coordinate you used to find the slope, to the formular to find the constant.
In this case i'm using the coordinate
(-2, 16)
y = mx + c
16 = -6(-2) + c
16 = 12 + c
c = 4
∴ The equation of the line is y = -6x + 4
The next step is to simply substitude in the x = 8 to the equation to find y.
y = -6(8) + 4
y = -48 + 4
y = -44
Answer:
becuase 2*3 is 6, and 2*4 is 8, and when you simplfy it is 1 and 1/2, which in decimal form is 1.5, making it less than 2
Answer:
I came up with 412cm^2
Step-by-step explanation:
10*12+(12*2)2+(10*2)2+6*8+(8*3)2+(6*3)2+(12*10-6*8)
