Answer:
Volume = 16 unit^3
Step-by-step explanation:
Given:
- Solid lies between planes x = 0 and x = 4.
- The diagonals rum from curves y = sqrt(x) to y = -sqrt(x)
Find:
Determine the Volume bounded.
Solution:
- First we will find the projected area of the solid on the x = 0 plane.
A(x) = 0.5*(diagonal)^2
- Since the diagonal run from y = sqrt(x) to y = -sqrt(x). We have,
A(x) = 0.5*(sqrt(x) + sqrt(x) )^2
A(x) = 0.5*(4x) = 2x
- Using the Area we will integrate int the direction of x from 0 to 4 too get the volume of the solid:
V = integral(A(x)).dx
V = integral(2*x).dx
V = x^2
- Evaluate limits 0 < x < 4:
V= 16 - 0 = 16 unit^3
Firstly you multiply 5 with everything in the brackets on the left side of = . and than you put t on the left side and change sign (if it was + then its going to be -) and numbers on right side and do the same with signs. then just calculate the rest
5(5t +1) = 25t - 7
25t + 5 = 25t - 7
25t - 25t = -7 + 5
0=-2
the statement is false
of
is 
Solution:
Given
of what number is
.
Let us first convert the mixed fraction into improper fraction.


Now, let us take the unknown number be x.


Do the cross multiplication.



Now, again change the improper fraction into mixed fraction.

Hence
of
is
.
Its a multiplication by -3 on each term, so I think you're gonna answer is by r=-3, maybe?