Question

Solve the following system of equations x^2+2y^2=59 2x^2+y^2=43

Answer 1

Answer: x = (-3,3), y = (-5,5)

Step-by-step explanation:

Add both of the equations together, for $3x^{2}+3y^{2} = 102$. Now we can divide both sides by 3, getting$x^2+y^2=34$. we subtract the first equation from our equation we just got, getting $y^2=25$ y= (5,-5). once we plug that in, we get $50+x^2 = 59$, $x^2 = 9$ x = (-3,3)