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lapo4ka [179]
3 years ago
10

Find the volume of a cylinder with a diameter of 10 inches and height of 20in

Mathematics
2 answers:
Arte-miy333 [17]3 years ago
8 0

Answer:

V=1570.8

Step-by-step explanation:

The volume of a cylinder with a diameter of 10 inches and height of 20 inches is 1570.8 inches.

I changed the diameter to radius to make it easier. The radius is half the diameter, making the radius 5 inches.

Formula: V=πr^2h

V=πr^2h=π·5^2·20≈1570.79633

weqwewe [10]3 years ago
3 0

Answer:

V = 500 pi in^3

or approximately 1570 in ^3

Step-by-step explanation:

The volume of a cylinder is given by

V = pi r^2 h  where r is  the radius and h is the height

The diameter is 10. so the radius is d/2 = 10/2 =5

V = pi (5)^2 * 20

V = pi *25*20

V = 500 pi in^3

We can approximate pi by 3.14

V = 3.14 * 500

V = 1570 in ^3

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2 years ago
Write the sum using summation notation, assuming the suggested pattern continues.100 + 121 + 144 + 169 + ... + n2 + ...
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Sigma_n=10 ^infinity n^2


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3 years ago
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2 years ago
Evaluate the six trigonometric functions of the angle 0.
Arturiano [62]

Given:

Right triangle

To find:

The six trigonometric functions of θ

Solution:

Hypotenuse = 18

Adjacent side to θ = 10

Opposite side to θ = ?

Using Pythagoras theorem:

\text {Hypotenuse}^2 = \text{adjacent}^2+\text{opposite}^2

18^2 =10^2+\text{opposite}^2

324=100+\text{opposite}^2

Subtract 100 from both sides.

224=\text{opposite}^2

Taking square root on both sides.

4\sqrt{14}=\text{opposite}

Using trigonometric ratio formula:

$\sin\theta =\frac{\text{opposite }}{\text{hypotenuse}}

$\sin\theta =\frac{4\sqrt{14} }{18}

$\csc\theta =\frac{\text{hypotenuse}}{\text{opposite }}

$\csc\theta =\frac{18}{4\sqrt{14} }

$\cos \theta=\frac{\text { adjacent side }}{\text { hypotenuse }}

$\cos \theta=\frac{10}{18}

$\sec \theta=\frac{\text { hypotenuse }}{\text { adjacent side }}

$\sec \theta=\frac{18 }{10}

$\tan \theta=\frac{\text { opposite side }}{\text { adjacent side }}

$\tan \theta=\frac{4\sqrt{14} }{10}

$\cot \theta=\frac{\text { adjacent side }}{\text { opposite side }}

$\cot \theta=\frac{10}{4\sqrt{14} }

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3 years ago
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Alexxandr [17]

Answer:

I don't know because you did not provide enough info

Step-by-step explanation:

but personally I think that I could pass the flyers out the fastest

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3 years ago
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