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IrinaK [193]
3 years ago
15

Someone plz help I don’t even know what this means

Mathematics
1 answer:
Vikentia [17]3 years ago
5 0
What you wanna do here is use a calculator, as "e" in mathematics refers to the "e" on a calculator. The tricky part about this question is that the answer for the equation is the given percentage, NOT the value for "x". From there, plug in the multiple choice answers for "x" and see which one works!

In this case, A is the correct answer. B is absurdly large, so I omitted it immediately in the attached picture.

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25x²+0x-1<br><br> Factor completely<br><br> Please provide an explanation if able
kati45 [8]

Answer:

(5x-1)(5x+1)

Step-by-step explanation:

4 0
3 years ago
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A square has a side of length of 12 centimeters. Which of he following is closest to the length of a diagonal of the square?
dimaraw [331]
<span>length of a diagonal of the square = </span>√(12^2 + 12^2)
= √(144 + 144)
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4 0
3 years ago
Hi hope ur having a great day but can u help me. Please. At least do up to number 4 but if u do the rest I will give brain list
lesya692 [45]

Answer:

2. 1400

3.4832

4. 1400

Step-by-step explanation:

8 0
3 years ago
The number of players in a tennis tournament is reduced by half (50%) after every round. In round 1 there are 256 player, in rou
Aleks04 [339]

Answer:

a_{n} = a_{1} (\frac{1}{2} )^{n - 1} where a_{1} = 256.

The number of players compete in round 7 will be 4.

Step-by-step explanation:

The number of players in a tennis tournament is reduced by half (50%) after every round. In round 1 there are 256 players, in round 2 there are 128 players, and so on.

So, the number of players is multiplied by \frac{1}{2} gives the number of players in the next round.

Therefore, the explicit function of number of players in nth round is given by  

a_{n} = a_{1} (\frac{1}{2} )^{n - 1} where a_{1} = 256.

Therefore, the number of players compete in round 7 will be a_{7} = 256 \times (\frac{1}{2} )^{(7 - 1)}  = 4. (Answer)

8 0
3 years ago
Find the slope of the line that passes through (2, 3) and (4, 4).
GuDViN [60]
For me cross multiplying works really well.
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3 years ago
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