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AlladinOne [14]
3 years ago
7

Select the correct answer.

Mathematics
2 answers:
vredina [299]3 years ago
6 0

Answer:

C

Step-by-step explanation:

The range is all the (y) values the function could have. The function's left end approaches negative infinity, while the right end approaches the asymptote of the function, y = 2.

So, the range is -∞ < y < 2. The answer is C.

I hope this helps :]

Zigmanuir [339]3 years ago
5 0

Answer: it is C just took this test

Step-by-step explanation:

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Which graph represents the function f(x)=
zhenek [66]

Step-by-step explanation:

you don't show us the choices.

anyway, the real graph must be similar to the one you are showing, as it goes to - and + infinity for x = 2.

because the denominator "x-2" will be 0 for x = 2.

but the horizontal limits are both y = +3 (and not 0).

because (3x-2)/(x-2) goes more and more to 3/1 the larger (or smaller in the - direction) x gets.

7 0
2 years ago
The first T-shirt you buy costs $7, and every additional shirt costs only $5. Let f(n) be the total cost of n shirts. F is a seq
Zina [86]

Answer:

f(n) = 2 + 5n. This is an arithmetic sequence.

Step-by-step explanation:

f(1) = 7

f(2) = 7 + 5

f(3) = 7 + 5 + 5 = 7 +10

f(4) = 7 + 5 + 5 + 5 = 7 + 15

In general,

f(n) = 7 + 5(n -1 )

        = 7 + 5n - 5

        = 2 + 5n

We have the sequence 7, 12, 17, 22, 27 …

This is an arithmetic sequence, because it is a sequence of numbers in which the <em>common difference</em> between consecutive terms is 5.

6 0
3 years ago
Please help no links
Nina [5.8K]

Answer:

x=5 y=-6

Step-by-step explanation:

3x+y=9 ------eqn1

y=4-2x -------eqn2

using substitution

put y=4-2x into eqn1

3x+4-2x=9

x=5

put x=5 into eqn2

y=4-2(5)

y=4-10

y=-6

8 0
3 years ago
Form the quadratic equation whose one root is 2 + 2^(1/2)​
Oksanka [162]

9514 1404 393

Answer:

  x^2 -4x +2 = 0

Step-by-step explanation:

The other root is the conjugate of the given one, so is 2-√2. The quadratic equation in factored form is then ...

  (x -2-√2)(x -2+√2) = 0

Expanding this, we get ...

  (x -2)^2 -(√2)^2 = 0

  x^2 -4x +4 -2 = 0

  x^2 -4x +2 = 0 . . . . the equation you're looking for

4 0
3 years ago
Please help me answer these 2 questions with a FULL explanation so I know how to do the rest myself. Giving brainliest.
sveticcg [70]

Answer to 1:

\frac{x^3}{2y^25}

First thing you want to do is combine like terms on the bottom. Since it's multiplication, all you have to do is add the exponents. So for x you'd get x raised to the -9 power and for y you'd get 2y raised to the power of 7

Second thing is the numerator of the fraction. Since this is raising what is inside the paranthesis to a power, you must multiply this power by the powers of x and y, respectively. You should get x raised to the power of -6 and y raised to the power of -18

Here's where it gets complicated. to rationalize the problem, you must add parts from the numerator and denominator or vice versa. You cannot have any negative exponents anywhere in the fraction.  So that means for x you have to add 9 to the x on the top to cancel out the -6 and rationalize the remaining x's. You should end up with x^3.

For y, you work the opposite way. Since the negatives are only on the top, you simply add 18 to the bottom y's and it remains rationalized.

If done correctly this should come out to x^3/2y^25

Answer to 2:

(x^20y^12)/256

First thing you can do on this one is to cancel out the x^0s. Anything to the power of 0 equals one so only the coefficients will remain. Multiply those together and you'll get 4.

Next you will rationalize the ys. Add the bottom 3 to the top to cancel out the denominator and you're left with y^-3. Leave it like this for now.

Now is the difficult part. You must take everything that is inside the parenthesis to the power of -4. That includes the coefficients and the exponents. 4^-4 = 1/256. This means that you now must move the coefficients to the bottom. You should currently have y^-3/(256x^5).

Now take the exponents to the power using the same rules as question 1. -3*-4 = 12 and 5*-4 = -20. You should now have y^12/(256x^-20)

Lastly, we must rationalize the denominator. To do so, move the x^-20 to the numerator and make the exponent positive. After doing this, you have the answer: (x^20y^12)/256

3 0
2 years ago
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