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kipiarov [429]
3 years ago
15

Remove all grouping symbols and combine like terms.

Mathematics
2 answers:
zubka84 [21]3 years ago
5 0
(3x+x^2)-\{4x^2-3x+[2x^2-x-(5x^2+4x)]\}\\\\=3x+x^2-\{4x^2-3x+[2x^2-x-5x^2-4x]\}\\\\=3x+x^2-\{4x^2-3x+[-3x^2-5x]\}\\\\=3x+x^2-\{4x^2-3x-3x^2-5x\}\\\\=3x+x^2-\{x^2-8x\}\\\\=3x+x^2-x^2+8x\\\\=11x
amid [387]3 years ago
4 0
( 3x + x ^2) - (4x^2 - 3x +(2x^2 - x - (5x^2 + 4x)))=\\
3x+x^2-4x^2+3x-(2x^2-x-5x^2-4x)=\\
-3x^2+6x-2x^2+x+5x^2+4x=\\
11x
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Answer:

2

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A geometric sequence means that each term is the previous term multiplied by a certain common ratio. For instance, here, -30 is 2 times -15, and -60 is 2 times -30. Hope this helps!

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3 years ago
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Answer:

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or

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Step-by-step explanation:

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3 0
3 years ago
Read 2 more answers
Two terms of an arithmetic sequence are a10=16 and a35=66 find the sum of the first 75 terms
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The sum of the first 75 terms of the arithmetic sequence that has 10th term as 16 and the 35th term as 66 is 5400.  

<h3>How to find the sum of terms using Arithmetic sequence formula</h3>

aₙ = a + (n - 1)d

where

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  • d = common difference
  • n = number of terms

Therefore, let's find a and d

a₁₀ = a + (10 - 1)d

a₃₅ = a + (35 - 1)d

Hence,

16 = a + 9d

66 = a + 34d

25d = 50

d = 50 / 25

d = 2

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a = 16 - 18

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Therefore, let's find the sum of 75 terms of the arithmetic sequence

Sₙ = n / 2 (2a + (n - 1)d)

S₇₅ = 75 / 2 (2(-2) + (75 - 1)2)

S₇₅ = 37.5 (-4 + 148)

S₇₅ = 37.5(144)

S₇₅ = 5400

learn more on arithmetic sequence here: brainly.com/question/1687271

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3 years ago
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Step-by-step explanation:

22

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4 years ago
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9/12 times 5 is 45/ 60 which is equal to 3/4 of a mile. I’m afraid I didn’t understand the question but I hope this helps.
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