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2 years ago

13

What is the volume of this figure?

1 answer:

umka2103 [35]2 years ago

5 0

Answer:216

Step-by-step explanation:

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Step by step to how to solve quadratic equation given the roots

Triss [41]

$\displaystyle\it\\\text{We have the equation: }\\\\ax^2+bx+c=0\\\\\text{We find the roots:}\\\\x_{12}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x_{1}=\frac{-b+\sqrt{b^2-4ac}}{2a}\\\\x_{2}=\frac{-b-\sqrt{b^2-4ac}}{2a}\\\\\text{If } b^2-4ac>0 \text{ then }x_1, x_2\in~R\\\\\text{If } b^2-4ac=0 \text{ then }x_1=x_2\in~R\\\\\text{If } b^2-4ac$

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3 0

3 years ago

The numbers of teams remaining in each round of a single-elimination tennis tournament represent a geometric sequence where an i

Anit [1.1K]

Answer:

$a_n = 128\bigg(\dfrac{1}{2}\bigg)^{n-1}$

Step-by-step explanation:

We are given the following in the question:

The numbers of teams remaining in each round follows a geometric sequence.

Let a be the first the of the geometric sequence and r be the common ration.

The $n^{th}$ term of geometric sequence is given by:

$a_n = ar^{n-1}$

$a_4 = 16 = ar^3\\a_6 = 4 = ar^5$

Dividing the two equations, we get,

$\dfrac{16}{4} = \dfrac{ar^3}{ar^5}\\\\4}=\dfrac{1}{r^2}\\\\\Rightarrow r^2 = \dfrac{1}{4}\\\Rightarrow r = \dfrac{1}{2}$

the first term can be calculated as:

$16=a(\dfrac{1}{2})^3\\\\a = 16\times 6\\a = 128$

Thus, the required geometric sequence is

$a_n = 128\bigg(\dfrac{1}{2}\bigg)^{n-1}$

4 0

3 years ago

Describe in words a situation that can be represented by 7÷2

Gelneren [198K]

Answer:

Example: There are 7 packs of candy, but only two people can share it equally.

Step-by-step explanation:

7/2= 3.5. If each person gets 3.5 bags, they both have an equal amount.

6 0

3 years ago

Plz help me with this

madreJ [45]

In order a0->a5: 1/3, 1, 3, 9, 27, 81

All you're doing is plugging the x-value in. So for a2, x=1, so y=3¹ which means y=3.

6 0

3 years ago

Read 2 more answers

5 (5) - -2 =<br><br> ( worth 10 points)

Irina-Kira [14]

Answer:

I think 27 is the answer

7 0

3 years ago

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