Given the vertices of the image, and preimage of this right isosceles triangle, we can find the line of reflection by definitively understanding how reflections work. Given the preimage contains the points A(-1,1), B(1,-1), and C(-3,-1). And that the image contains the points A'(5,1), B'(3,-1), C'(7,-1). We can differentiate the corresponding points and apply them to the rules of a reflection. if figure Z is reflected over x = n,

than Z'(x,y) = Z(-x+2n,y). Logically, you can see that this pattern resembles all three coordinates for the transformation. i.e A'(5,1) = A(--1+2n,1) ; (1+2n,1) = (5,1) ; 1 + 2n = 5, 2n = 4, n = 2

we can prove this by using another point:

B'(3,-1) = (-1+2n,-1) = (-1 + 4, -1) = (3,-1)

Hopefully you understand,

<u>Pls mark brainliest this took me a very long time.</u>

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2 years ago