N³ - 2n² - 15n = 0
"n"
n (n² + 2n - 15) = 0
n = 0
n² + 2n - 15 = 0
Δ = (2)² - 4(1)(-15)
Δ = 4 + 60 = 64
n' = (-2+8) / 2 = 6/2 =3
n'' = (-2-8) / 2 = -10/2 = -5
Solution:
S {-5 , 0 , 3 }
<span>Yes, you can do this. It is important to note however that inside of lines, the sides of a this quadrilateral are better described as segments. A quadrilateral has four sides, and if there are two sets of parallel sides, it is a parallelogram. A rectangle is a parallelogram, but it has four right angles. If you take a rectangle, and change the angles, you will still have a parallelogram that is no longer a rectangle. It will have two sets of parallel sides, but no right angles. Opposite angles will be congruent.</span>
Answer:
[4, -1]
Step-by-step explanation:
Using the Elimination Method:
3x + y = 11
5x - y = 21
__________
8x = 32
__ ___
8 8
x = 4 [Plug this back into both equations to get the y-coordinate of -1]; -1 = y
The <em>y</em>'s are already <em>additive</em><em> </em><em>inverses</em><em> </em>[result in 0], canceling each other out.
I am joyous to assist you anytime.
Step-by-step explanation:
0.962962963 is the answer pls brainliesttt
