Answer:
9.9 years
Step-by-step explanation:
A = P e ^(rt)
Where A is the amount in the account
P is the amount invested
R is the interest rate
t is the time
P = 8500
r =7% = .07
A = 17000
Substituting into the equation
17000=8500 e^(.07t)
Divide each side by 8500
17000/8500=8500/8500 e^(.07t)
2 = e^(.07t)
Take the natural log of each side
ln (2) = ln e^(.07t)
ln(2) = .07t
Divide each side by .07
ln(2)/.07 = .07t/.07
ln(2)/.07 = t
9.902102579=t
Rounding to one decimal place
9.9 years
The average rate of change is -5 per month
<h3>How to determine the average rate of change?</h3>
The interval is given as:
July to December
From the graph, we have:
July = 110
December = 30
The average rate of a function over the interval (a, b) is calculated as:
Rate = [f(b) - f(a)]/[b - a]
So, we have:
Rate = (30 - 110)/(December- July)
This gives
Rate = (30 - 110)/(12 - 7)
Evaluate
Rate = -16
Hence, the average rate of change is -5 per month
Read more about average rate of change at:
brainly.com/question/23715190
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Answer:
1 5 7 35
Step-by-step explanation: im a differnet breed duh
Answer:
y = (5-2x)/7 = 5/7 - 2x/7. option C
Step-by-step explanation:
here's your solution
=> 7y + 2x = 5
=> 7y = 5 - 2x
=> y = (5-2x)/7
The answer is C
y=kx. where k is a constant
sub y=34,x=2
2k=34
k=17
