Answer:
148ft
Step-by-step explanation:
To solve this question, you'll have to imagine the statue makes a right angle triangle with the base since it has an angle of elevation from the base to the top of the torch.
Assuming the height from the pedestal to the top of the torch is y
The height of the statue is x
But we know the height of the pedestal = 150ft
The distance from the observer to the base of the pedestal = 250ft
And the angle of elevation = 50°
See attached document for better illustration.
Tanθ = opposite / adjacent
θ = 50°
Adjacent = 250
Opposite = y
Tan50 = t / 250
y = 50 × tan50
y = 50 × tan50
y = 50 × 1.1917
y = 297.925ft
The height of the statue from the base of the pedestal to the top of the torch is 297.925ft
The height of the statue = x
x = (height of the statue + height of the pedestal) - height of the pedestal
x = y - 150
x = 297.925 - 150
x = 147.925ft
Approximately 148ft
The height of the statue is 148ft
Answer:
50.25 cm trust me
Step-by-step explanation:
5.25 cm
Answer:
A = 388.58 cm^2
Step-by-step explanation:
For a cone whose base has a radius R, and a hypotenuse S, the area is:
A = pi*R^2 + pi*R*S
Where pi = 3.14
In this case, we can see that the diameter is: 15cm
Then the radius, half of the diameter, is:
R = 15cm/2 = 7.5cm
The hypotenuse is 9cm, then S = 9cm
A = 3.14*(7.5cm)^2 + 3.14*(9cm)*(7.5cm) = 388.575 cm^2
Rounding to two decimal places, we need to look at the third one, which is a five, so we need to round up:
A = 388.58 cm^2
Answer:
Qu. 8 = A (50) = 25w as 125w x 125l = Area ; this because perimeter 500ft would always be a 3:5 ratio to the larger area. Therefore perimeter is 125+125 +125 +125 and = 500ft. However we can prove if 125 is any length or width then A(50)= 1/5 = 25 Qu 9)= I think last 2 are a function. Qu 10) Answer B is correct.
Step-by-step explanation:
Given:
The given digits are 1,2,3,4,5, and 6.
To find:
The number of 5-digit even numbers that can be formed by using the given digits (if repetition is allowed).
Solution:
To form an even number, we need multiples of 2 at ones place.
In the given digits 2,4,6 are even number. So, the possible ways for the ones place is 3.
We have six given digits and repetition is allowed. So, the number of possible ways for each of the remaining four places is 6.
Total number of ways to form a 5 digit even number is:
Therefore, total 3888 five-digit even numbers can be formed by using the given digits if repetition is allowed.
