Answer:
i think of
Step-by-step explanation:
c is your answer
Answer:
A. The first 2 are equivalent expressions.
B. The last 2 are equavalent expressions.
Answer:
16
Step-by-step explanation:
How many times more intense is an earthquake measuring 6.8 on the Richter scale than one measuring 5.6?
Given:
Earthquake 1 : magnitude = 6.8
Earthquake 2: magnitude = 5.6
The intensity of an earthquake
I1 / I2
log I1 /s = 6.8
log I2 /s = 5.6
(log I2 /s) - (log I1 /s) = 6.8 - 5.6
(log I2 /s) - (log I1 /s) = 1.2
log(I2 / I1) = 1.2
I2 / I1 = 10^1.2
I2 / I1 = 15.8489
= 16
6.8 earthquake is about 16 times more intense than earthquake measuring 5.6
Answer:
3y-24 is 3(y-8) xoxo
Step-by-step explanation:
The expression 3y−24 factored using the GCF is
To find out GCF, we break the factors
3y -> 3 times y
24 -> 2 times 2 times 2 times 3
Here we have 3 in common .
From the factors we have common factor 3
So GCF that is Greatest common factor is 3
GCF of 3y-24 is 3
Take out 3 in common
3y-24 \ is \ 3(y-8)
Answer:
-162
Step-by-step explanation:
x²+24x-18=x²+24x+12²-12²-18=(x+12)²-162
(x+12)²≥0
(x+12)²-162≥-162
⇒ the minimum value of the function is -162