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2 years ago

5

I want to read 4 books over the next month. My bookshelf has 12 different books. In how many ways can I choose which books to re

ad over the next month, without regard to the order that I read them?

1 answer:

shusha [124]2 years ago

8 0

Answer:

Step-by-step explanation:

You are going to choose 4 books in any order.

Four = 12! /(8!4!) Remember that order doesn't matter, so we have 12C4

495

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8x-2(x+1)=2(3x-1)<br> A. 0<br> b.2<br> C.no solution <br> D.identity

fomenos

8x - 2x(x+1) = 2(3x-1)

First, expand to remove parenthesis. / Your problem should look like:

8x - 2x - 2 = 6x - 2

Second, subtract 8x - 2x -2 to get 6x - 2. / Your problem should look like:

6x - 2 = 6x - 2

Third, both sides are equal, so there are infinite solutions. The equation is always true, meaning identity

Answer: Infinite solutions

Shoutout to: @Exvited

live

7 0

3 years ago

x - 2y = 3 5x + 3y = 2 The lines whose equations are shown intersect at which point? (1, -1) (-1, 1) (0, 3/2)

gtnhenbr [62]

I would solve the first equation for x and then sub that value into x in the second equation. That's the easiest way. x - 2y = 3 solved for x is x = 2y+3. Now sub that in for x in the second equation: 5(2y+3)+3y=2 and 10y + 15 + 3y = 2. 13y = -13, and y = -1. Now sub that y value into either equation to solve for x: x = 2(-1) + 3 gives us an x value of x = 1. Therefore, your solution to this system is (1, -1), first choice above.

4 0

2 years ago

A 1/17th scale model of a new hybrid car is tested in a wind tunnel at the same Reynolds number as that of the full-scale protot

Olegator [25]

Answer:

The ratio of the drag coefficients $\dfrac{F_m}{F_p}$ is approximately 0.0002

Step-by-step explanation:

The given Reynolds number of the model = The Reynolds number of the prototype

The drag coefficient of the model, $c_{m}$ = The drag coefficient of the prototype, $c_{p}$

The medium of the test for the model, $\rho_m$ = The medium of the test for the prototype, $\rho_p$

The drag force is given as follows;

$F_D = C_D \times A \times \dfrac{\rho \cdot V^2}{2}$

We have;

$L_p = \dfrac{\rho _p}{\rho _m} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_m} \right)^2 \times L_m$

Therefore;

$\dfrac{L_p}{L_m} = \dfrac{\rho _p}{\rho _m} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_m} \right)^2$

$\dfrac{L_p}{L_m} =\dfrac{17}{1}$

$\therefore \dfrac{L_p}{L_m} = \dfrac{17}{1} =\dfrac{\rho _p}{\rho _p} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_p} \right)^2 = \left(\dfrac{V_p}{V_m} \right)^2$

$\dfrac{17}{1} = \left(\dfrac{V_p}{V_m} \right)^2$

$\dfrac{F_p}{F_m} = \dfrac{c_p \times A_p \times \dfrac{\rho_p \cdot V_p^2}{2}}{c_m \times A_m \times \dfrac{\rho_m \cdot V_m^2}{2}} = \dfrac{A_p}{A_m} \times \dfrac{V_p^2}{V_m^2}$

$\dfrac{A_m}{A_p} = \left( \dfrac{1}{17} \right)^2$

$\dfrac{F_p}{F_m} = \dfrac{A_p}{A_m} \times \dfrac{V_p^2}{V_m^2}= \left (\dfrac{17}{1} \right)^2 \times \left( \left\dfrac{17}{1} \right) = 17^3$

$\dfrac{F_m}{F_p} = \left( \left\dfrac{1}{17} \right)^3$ = (1/17)^3 ≈ 0.0002

The ratio of the drag coefficients $\dfrac{F_m}{F_p}$ ≈ 0.0002.

5 0

2 years ago

Please help me Solve for x. Have to show work

REY [17]

A -17 3/4< x so u have to simplify-17 3/4 by multiply 17*4=68+3=71/4 so the x stands for -71/4 and it has to be 4 as the denominator because it it the denominator for the question.
B, C, D are also the same answer-17/4
And for 15 3/4<-2+ x it is also the same answer

6 0

2 years ago

What number is greater 0.111 or 1.001. also 1.11 or 1.01

Paul [167]

1.001 is greater than 0.111 because the 1 is automatically greater than zero. 1.11 is greater than 1.01 because there is a place in the tenths place in 1.11 but none for 1.01.

4 0

2 years ago

Read 2 more answers