Answer:0.2588
Step-by-step explanation:
Any number inside the modulus sign becomes positive. This means
and so we have,

Solving these gives us


However if we check the second solution in the original equation we obtain
. This is false and so
can't be a solution.
Therefore the only solution is
.
(Note: I'm not sure why the second solution didn't work but when there's a modulus sign involved it always pays to check your final answers to be sure. I'll have a think about it but in case you find out before I do, I'd be interested to know in the comments.)
Yes because all sides would be equal to 5 which would give you 5*4 = 20 units.
1.They basically all did one big bug,not separate hugs with different bears.
Answer:
1
1 is the only integer that can go into 5 as 5 is a prime number