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3241004551 [841]

2 years ago

12

Find the change below as a percentage. Then choose whether it is a percent of incease ror a percent of decrease. Change from 22

grams to 33 grams.

1 answer:

melisa1 [442]2 years ago

7 0

$\dfrac{33}{22}\times100 =150$

Ans: 150%, a percent of incease

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Mila [183]

<h3>Answer: 0.1319</h3>

==========================================

Work Shown:

$P(x) = (_n C_x)*(p)^x*(1-p)^{n-x}\\\\P(14) = (_{15} C_{14})*(0.8)^{14}*(1-0.8)^{15-14}\\\\P(14) = 15*(0.8)^{14}*(0.2)^{1}\\\\P(14) \approx 0.13194139533312 \\\\P(14) \approx \boldsymbol{0.1319} \\\\$

Side note: you can use the nCr formula to compute $_{15} C_{14}$ ; however, it's much quicker to use the shortcut formula $_{n} C_{n-1} = n$ . You can also use Pascal's Triangle to find the value of $_{15} C_{14}$

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mario62 [17]

Answer:

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Step-by-step explanation:

Check answer:

Distribute 3(21+16)

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LekaFEV [45]

$= > x + \frac{1}{3} = 9$

$\text{Add} \: - \frac{1}{3} \: \text{ on both sides ,}$

$= > x + \frac{1}{3} - \frac{1}{3} = 9 - \frac{1}{3} \\ \\ \\ \\ = > x = \frac{(9 \times 3) - 1}{3} \\ \\ \\ \\ = > x = \frac{27 - 1}{3} \\ \\ \\ \boxed{ \bold{= > x = \frac{26}{3} }} \\ \\ \\ or , \boxed{ \bold{ \: x = 8. \bar{6}}}$

Hence,

$Value \: \: \: of \: \: x \: \: is \: \frac{26}{3} \: \: \: or \: \: \: 8. \bar{6}$

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3 years ago