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4 years ago

11

Anna put $500 into a savings account and made no more deposits or withdrawals. The account earns 2% simple interest per year. Ho

w much money will be in the account after 5 years?

1 answer:

castortr0y [4]4 years ago

4 0

Answer:

$552.04

Step-by-step explanation:

Lauren, use the compound amount formula: A = P(1 + r)^n.

Here P is the principal and is $500; r is the annual interest rate as a decimal fraction, and n is the number of years.

After 5 years, Anna will have: $500(1 + 0.02)^5 = $552.04

You might be interested in

What is the greatest common factor of 6a²b3 + 15ab^5– 9a^3b^2??

Roman55 [17]

Answer:

3ab^2

Step-by-step explanation:

Factor 6a^2b^3

= 2 * 3 * a * a * b * b * b

Factor 15ab^5

= 3 * 5 * a * b * b * b * b * b

Factor 9a^3b^2

3 * 3 * a * a * a * b * b

Common Factor

= 3 * a * b * b

Simplify

= 3ab^2

5 0

3 years ago

Find the values of A B C AND D of <br> 4x^2 (2x^3+5x)= Ax^B +Cx^D

iren2701 [21]

The values are $A=8, B=5, C= 20$ and $D=3$

Explanation:

The expression is $4x^{2} (2x^{3} +5x)=Ax^{B} +Cx^{D}$

Simplifying, we get,

$8x^{5} +20x^3=Ax^{B} +Cx^{D}$

Since, both sides of the expression are equal, we can equate the corresponding values of A, B, C and D.

Thus, we get,

$8 x^{5}=A x^{B}$ ⇒ $A=8$ and $B=5$

Also, equating, $20 x^{3}=C x^{D}$ , we get,

$C=20$ and $D=3$

Thus, the values are $A=8, B=5, C= 20$ and $D=3$

3 0

3 years ago

The shoes that Sofia wanted to buy at the mall were marked down from $30 to $24. What is the percentage of discount?

Nataliya [291]

30-24=6
6/30=1/5 aka 20%

The answer is 20%

Hope this helps.

8 0

4 years ago

What is the median of those in the the picture please help

Molodets [167]

Answer:

Median is 24.5

Step-by-step explanation:

Median is the middle number in a set of numbers. If we have two middle numbers, we get the average. And from the question, listing them out, we have this

0,1, 2, 3,4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49.

The middle number here is 24 and 25. Getting their average will be 24.5

5 0

4 years ago

In a certain Algebra 2 class of 30 students, 19 of them play basketball and 12 of them play baseball. There are 8 students who p

Alenkinab [10]

Answer:

Probability that a student chosen randomly from the class plays basketball or baseball is $\frac{23}{30}$ or 0.76

Step-by-step explanation:

Given:

Total number of students in the class = 30

Number of students who plays basket ball = 19

Number of students who plays base ball = 12

Number of students who plays base both the games = 8

To find:

Probability that a student chosen randomly from the class plays basketball or baseball=?

Solution:

$P(A \cup B)=P(A)+P(B)-P(A \cap B)$ ---------------(1)

where

P(A) = Probability of choosing a student playing basket ball

P(B) = Probability of choosing a student playing base ball

P(A \cap B) = Probability of choosing a student playing both the games

<u>Finding P(A)</u>

P(A) = $\frac{\text { Number of students playing basket ball }}{\text{Total number of students}}$

P(A) = $\frac{19}{30}$ --------------------------(2)

<u>Finding P(B)</u>

P(B) = $\frac{\text { Number of students playing baseball }}{\text{Total number of students}}$

P(B) = $\frac{12}{30}$ ---------------------------(3)

<u>Finding $P(A \cap B)$ </u>

P(A) = $\frac{\text { Number of students playing both games }}{\text{Total number of students}}$

P(A) = $\frac{8}{30}$ -----------------------------(4)

Now substituting (2), (3) , (4) in (1), we get

$P(A \cup B)= \frac{19}{30} + \frac{12}{30} -\frac{8}{30}$

$P(A \cup B)= \frac{31}{30} -\frac{8}{30}$

$P(A \cup B)= \frac{23}{30}$

7 0

3 years ago