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dem82 [27]
1 year ago
13

You are solving a measurement problem where the numbers 4.5160 x 10−3, 2.09 x 107, and 5.8 x 103 are multiplied. how many sign

ificant digits should the product have?
Mathematics
1 answer:
Natalija [7]1 year ago
5 0

The product should have a 1 significant digit.

<h3>Scientific notations</h3>

When multiplying Scientific notations, the significant figure of the final result must be approximated to the scientific notation that has the least decimal place.

From the question given, if we 4.5160 x 10^3, 2.09 x 107, and 5.8 x 10^3 are multiplied, the product should have 1 significant digits since the least decimal value that occur in question is 1dp

Hence the product should have a 1 significant digit.

Learn more on product of decimals here: brainly.com/question/28416295

#SPJ1

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I need help the question is what is the are of the composite figure
AlladinOne [14]

Answer:

Option 4

Step-by-step explanation:

Area of a trapezoid = \frac{1}{2}(b_1+b_2)h

Here, b_1 and b_2 are the bases and 'h' is the height between the bases.

Area of the composite figure = Area of two trapezoids given

                                                = \frac{1}{2}(12+12)14+\frac{1}{2}(25+31)11

                                                = \frac{1}{2}(24)(14)+\frac{1}{2}(56)(11)

                                                = 168 + 308

                                                = 476 square ft

Option 4 is the answer.

3 0
2 years ago
Determine,in each of the following cases, whether the described system is or not a group. Explain your answers. Determine what i
zheka24 [161]

Answer:

(a) Not a group

(b) Not a group

(c) Abelian group

Step-by-step explanation:

<em>In order for a system <G,*> to be a group, the following must be satisfied </em>

<em> (1) The binary operation is associative, i.e., (a*b)*c = a*(b*c) for all a,b,c in G </em>

<em>(2) There is an identity element, i.e., there is an element e such that a*e = e*a = a for all a in G </em>

<em> (3) For each a in G, there is an inverse, i.e, another element a' in G such that a*a' = a'*a = e (the identity) </em>

<em> </em>

If in addition the operation * is commutative (a*b = b*a for every a,b in G), then the group is said to be Abelian

(a)  

The system <G,*> is not a group since there are no identity.  

To see this, suppose there is an element e such that  

a*e = a

then  

a-e = a which implies e=0

It is easy to see that 0 cannot be an identity.

For example  

2*0 = 2-0 = 2

Whereas

0*2 = 0-2 = -2

So 2*0 is not equal to 0*2

(b)

The system <G,*> is not a group either.

If A is a matrix 2x2 and the determinant of A det(A)=0, then the inverse of A does not exist.

(c)

The table of the operation G is showed in the attachment.

It is evident that this system is isomorphic under the identity map, to the cyclic group

\mathbb{Z}_{5}

the system formed by the subset of Z, {0,1,2,3,4} with the operation of addition module 5, which is an Abelian cyclic group

We conclude that the system <G,*> is Abelian.

Attachment: Table for the operation * in (c)

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3 years ago
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lbvjy [14]
Yea he will
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inn [45]

Answer:

y = -3

Step-by-step explanation:

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