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anzhelika [568]
3 years ago
11

Show that the triangles are similar by comparing the ratios of the corresponding sides. Simplify your answer completely in order

to be able to compare the ratios of the corresponding sides. Please help

Mathematics
1 answer:
kirill [66]3 years ago
4 0

Answer/Step-by-step explanation:

AC = 1.2

AB = 4

BC = 2.6

DF = 3

DE = 10

EF = 6.5

Thus:

\frac{DE}{AB} = \frac{10}{4} = \frac{5}{2}

\frac{DF}{AC} = \frac{3}{1.2} = \frac{3*10}{1.2*10} = \frac{30}{12} = \frac{5}{2}

\frac{EF}{BC} = \frac{6.5}{2.6} = \frac{6.5*10}{2.6*10} = \frac{65}{26} = \frac{5}{2}

The ratio of their corresponding sides are all equal to ⁵/2. Therefore, both triangles are similar.

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