Answer:
The numbers
such that the average value of
on the interval [0, b] is equal to 8 are
and
.
Step-by-step explanation:
The mean value of function within a given interval is given by the following integral:

If
,
,
and
, then:





The roots of this polynomial are determined by the Quadratic Formula:
and
.
The numbers
such that the average value of
on the interval [0, b] is equal to 8 are
and
.
I get the answer being the same y= -1/2x +
Because b in intercept form is "0"
I used
m=y2-y1/x2-x1
M=-3-2/6-4
M=-5/10
M=-1/2
(-4,2)
Y=mx+b
2=-1/2 (-4)+b
B=2-(-1/2)(-4)
B=0
I did the same for second point
And got "0" for b
So my answer is get
Y=-1/2x
Unless someone else gets something else different.
I hope somewhat helps
In scientific notation it would just be 3.06 x 0, it is the same thing as the regular notation.
We can check to see if (x - 2)(x - 9)(x - 1) is the factored form of x^3 + 8x^2 - 11x - 18 by using foil.
(x - 2)(x - 9)(x - 1)
(x - 2)x^2 - x - 9x + 9
Combine like terms.
(x - 2)x^2 - 10x + 9
FOIL again.
x^3 - 10x^2 + 9x - 2x^2 + 20x - 18
Combine like terms.
x^3 - 12x^2 + 29x - 18
<h3><u>The listed factors are not true factors of the given polynomial.</u></h3>