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anzhelika [568]
3 years ago
11

Show that the triangles are similar by comparing the ratios of the corresponding sides. Simplify your answer completely in order

to be able to compare the ratios of the corresponding sides. Please help

Mathematics
1 answer:
kirill [66]3 years ago
4 0

Answer/Step-by-step explanation:

AC = 1.2

AB = 4

BC = 2.6

DF = 3

DE = 10

EF = 6.5

Thus:

\frac{DE}{AB} = \frac{10}{4} = \frac{5}{2}

\frac{DF}{AC} = \frac{3}{1.2} = \frac{3*10}{1.2*10} = \frac{30}{12} = \frac{5}{2}

\frac{EF}{BC} = \frac{6.5}{2.6} = \frac{6.5*10}{2.6*10} = \frac{65}{26} = \frac{5}{2}

The ratio of their corresponding sides are all equal to ⁵/2. Therefore, both triangles are similar.

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Find the numbers b such that the average value of f(x) = 7 + 10x − 9x2 on the interval [0, b] is equal to 8.
barxatty [35]

Answer:

The numbers b such that the average value of f(x) = 7 +10\cdot x - 9\cdot x^{2} on the interval [0, b] is equal to 8 are b_{1} \approx 1.434 and b_{2} \approx 0.232.

Step-by-step explanation:

The mean value of function within a given interval is given by the following integral:

\bar f = \frac{1}{b-a}\cdot \int\limits^b_a {f(x)} \, dx

If f(x) = 7 +10\cdot x - 9\cdot x^{2}, a = 0, b = b and \bar f = 8, then:

\frac{1}{b}\cdot \int\limits^b_0 {7+10\cdot x -9\cdot x^{2}} \, dx = 8

\frac{7}{b}\int\limits^b_0 \, dx  + \frac{10}{b}  \int\limits^b_0 {x}\, dx - \frac{9}{b}  \int\limits^b_0 {x^{2}}\, dx = 8

\left(\frac{7}{b} \right)\cdot b + \left(\frac{10}{b} \right)\cdot \left(\frac{b^{2}}{2} \right)-\left(\frac{9}{b} \right)\cdot \left(\frac{b^{3}}{3} \right) = 8

7 + 5\cdot b - 3\cdot b^{2} = 8

3\cdot b^{2}-5\cdot b +1 = 0

The roots of this polynomial are determined by the Quadratic Formula:

b_{1} \approx 1.434 and b_{2} \approx 0.232.

The numbers b such that the average value of f(x) = 7 +10\cdot x - 9\cdot x^{2} on the interval [0, b] is equal to 8 are b_{1} \approx 1.434 and b_{2} \approx 0.232.

7 0
3 years ago
Idk how to do this honestly
Anuta_ua [19.1K]
I get the answer being the same y= -1/2x +

Because b in intercept form is "0"

I used
m=y2-y1/x2-x1
M=-3-2/6-4
M=-5/10
M=-1/2

(-4,2)
Y=mx+b
2=-1/2 (-4)+b
B=2-(-1/2)(-4)
B=0

I did the same for second point
And got "0" for b


So my answer is get
Y=-1/2x


Unless someone else gets something else different.

I hope somewhat helps
8 0
3 years ago
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Andru [333]
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How can i write 3.06 in standard form for scientific notation
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3 0
3 years ago
Is g(x)= (x-2)(x-9)(x-1) the factored form of f(x)=x^3+8x^2-11x-18
strojnjashka [21]

We can check to see if (x - 2)(x - 9)(x - 1) is the factored form of x^3 + 8x^2 - 11x - 18 by using foil.

(x - 2)(x - 9)(x - 1)

(x - 2)x^2 - x - 9x + 9

Combine like terms.

(x - 2)x^2 - 10x + 9

FOIL again.

x^3 - 10x^2 + 9x - 2x^2 + 20x - 18

Combine like terms.

x^3 - 12x^2 + 29x - 18

<h3><u>The listed factors are not true factors of the given polynomial.</u></h3>
5 0
3 years ago
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