Okay here we go!
The answer is D.
Because when you solve the equation you get 2 and that means the arrow has to be or end at 2.
HOPE THIS HELPED! :)
The volume of the region R bounded by the x-axis is: 
<h3>What is the volume of the solid revolution on the X-axis?</h3>
The volume of a solid is the degree of space occupied by a solid object. If the axis of revolution is the planar region's border and the cross-sections are parallel to the line of revolution, we may use the polar coordinate approach to calculate the volume of the solid.
In the graph, the given straight line passes through two points (0,0) and (2,8).
Therefore, the equation of the straight line becomes:

where:
- (x₁, y₁) and (x₂, y₂) are two points on the straight line
Thus, from the graph let assign (x₁, y₁) = (0, 0) and (x₂, y₂) = (2, 8), we have:

y = 4x
Now, our region bounded by the three lines are:
Similarly, the change in polar coordinates is:
where;
- x² + y² = r² and dA = rdrdθ
Now
- rsinθ = 0 i.e. r = 0 or θ = 0
- rcosθ = 2 i.e. r = 2/cosθ
- rsinθ = 4(rcosθ) ⇒ tan θ = 4; θ = tan⁻¹ (4)
- ⇒ r = 0 to r = 2/cosθ
- θ = 0 to θ = tan⁻¹ (4)
Then:


Learn more about the determining the volume of solids bounded by region R here:
brainly.com/question/14393123
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Area of the middle rectangular section = length x width = 35 x 20 = 700 square cm.
The radius of the circular sections is 25 cm
Area of a full circle is pi x r^2 = 3.14 x 25^2 = 1962.5 square cm.
There are two quarter circles which is 1/2 of a circle. The area of those would be 1962.5/2 = 981.25 square cm.
Total area of the figure = 700 + 981.25 = 1681.25 square cm
Answer:
8
Step-by-step explanation:
to get x alone you divide the 2 away on both sides, getting x = 8. To check multiply 8 by 2 and you get 16.
Hope this helps!
<h2>
<u>Answer:
</u></h2>
The bearing of B from A is 28 degrees, approximately
The bearing of A from B is 180+28=208 degrees, approximately.
Step-by-step explanation:
The bearing of B from A is 28 degrees, approximately
The bearing of A from B is 180+28=208 degrees, approximately.
The reason for approximation is from distortion of image.
See attached image to understand ohw the measurement has been obtained.