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3 years ago

You pick a card at random. Without putting the first card back, you pick a second card at

Mathematics

1 answer:

PSYCHO15rus [73]3 years ago

6 0

Answer:

anality

Step-by-step explanation:

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Solve this If you can

ASHA 777 [7]

Answer:

I cannot solve this okay

4 0

3 years ago

The sum of five consecutive multiples of 4 is 20.Find the smallest integer.

Aloiza [94]

Answer:

The smallest integer is -4.

Step-by-step explanation:

Let the smallest integer be x.

Since the integers are all multiples of 4, they are

=> x, x+4, x+8, x+12 and x+16

=> x + x+4 + x+8 + x+12 + x+16 = 20

=> 5x + 40 = 20

Subtract 40 from both sides of the equation

5x +40 - 40 = 20 - 40

5x = -20

Divide both sides by the coefficient of x(which is 5)

$\frac{5x}{5} = \frac{-20}{5}$

x = -4

∴ the smallest integer is -4.

Hope this helps!!!

6 0

3 years ago

The graph shows the relationship between the number of apples and their cost. For the point (1, r), what is the value of r?

3241004551 [841]

Answer:

Step-by-step explanation:

When you check the point that is on X, it is a little over halfway to the point 1,2. It would be like 1,1.5 or 1,1.6.

5/3 is the equivalent to 1.6 so that answer would make the most sense.

4 0

3 years ago

Read 2 more answers

Can someone help me in this plssss I really need it

kompoz [17]

Answer:

$\boxed{-3xy^{2}\sqrt [3] {2x^{2}}}$

Step-by-step explanation:

Your expression is

$\sqrt [3] {-54x^{5}y^{6}}$

Here's how I would simplify it.

$\begin{array}{rcll}\sqrt [3] {-54x^{5}y^{6}} & = & \sqrt [3] {(-1)^{3}\times 2 \times 27 \times x^{2} \times x^{3} \times y^{6}} & \text{Factored the cubes}\\& = & \sqrt [3] {(-1)^{3} \times 3^{3}\times x^{3} \times y^{6}\times 2 \times x^{2}} & \text{Grouped the cubes}\\\end{array}$

$\begin{array}{rcll}& = & \sqrt [3] {(-1)^{3} \times {3^{3}\times x^{3} \times y^{6}}} \times\sqrt [3] { 2 \times x^{2}} & \text{Separated the cubes}\\&=& \mathbf{-3xy^{2}\sqrt [3] {2x^{2}}} & \text{Took cube roots}\\\end{array}$

$\text{The simplified expression is $\boxed{\mathbf{-3xy^{2}\sqrt [3] {2x^{2}}}}$}$

6 0

4 years ago

Pls just look at the pic to find the question

kvasek [131]

If you count the squares, you will see that there is 3 squares or units between Q and R and 7 squares or units between P and Q
Answer is D.

5 0

3 years ago