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OlgaM077 [116]
3 years ago
8

A continuous probability distribution having a rectangular shape, where the probability is evenly distributed over an interval o

f numbers is a(n) ____________ distribution.
Mathematics
1 answer:
aleksklad [387]3 years ago
8 0

Answer:

A continuous probability distribution having a rectangular shape, where the probability is evenly distributed over an interval of numbers is a(n) __uniform__________ distribution

Step-by-step explanation:

Given that there is a  continuous probability distribution having a rectangular shape, where the probability is evenly distributed over an interval of numbers

Since the pdf is rectangular in shape and total probability is one we can say all values in the interval would be equally likely

Say if the interval is (a,b) P(X) = p the same for all places

Since total probability is 1,

we get integral of P(X)=p(b-a) =1

Or p= \frac{1}{b-a}

this is nothing but a uniform distribution continuous defined in the interval

A continuous probability distribution having a rectangular shape, where the probability is evenly distributed over an interval of numbers is a(n) __uniform__________ distribution

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Translate mathematical word sentence into written expression: a/2=9
Burka [1]

Answer:

a/2 = 9

  • <em>a</em> divided by 2 gives 9.
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3 years ago
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Anettt [7]

Answer:

The ball shall keep rising tills its velocity becomes zero. Let it rise to a height h feet from point of projection.

Step-by-step explanation:

Let us take the point of projection of the ball as origin of the coordinate system, the upward direction as positive and down direction as negative.

Initial velocity u with which the ball is projected upwards = + 120 ft/s

Uniform acceleration a acting on the ball is to acceleration due to gravity = - 32 ft/s²

The ball shall keep rising tills its velocity becomes zero. Let it rise to a height h feet from point of projection.

Using the formula:

v² - u² = 2 a h,

where

u = initial velocity of the ball = +120 ft/s

v = final velocity of the ball at the highest point = 0 ft/s

a = uniform acceleration acting on the ball = -32 ft/s²

h = height attained

Substituting the values we get;

0² - 120² = 2 × (- 32) h

=> h = 120²/2 × 32 = 225 feet

The height of the ball from the ground at its highest point = 225 feet + 12 feet = 237 feet.

7 0
3 years ago
How many 2/3 are in 3 1/3
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4 years ago
Is 2 hours and 30 minutes more or less than 10% of a day?
belka [17]
10% of the day =10/100×24=2 hours 24 minutes therefore 2 hours 30 minutes is more than 10% of a day
8 0
3 years ago
Jane wishes to bake an apple pie for dessert. The baking instructions say that she should bake the pie in an oven at a constant
pychu [463]

Answer:

A=152

K= -Ln(0.5)/14

Step-by-step explanation:

You can obtain two equations with the given information:

T(14 minutes) = 114◦C

T(28 minutes)=152◦C

Therefore, you have to replace t=14, T=114 and t=28, T=152 in the given equation:

114=190-Ae^{-14k} (I) \\152=190-Ae^{-28k}(II)

Applying the following property of exponentials numbers in (II):

e^{a}.e^{b}=e^{a+b}

Therefore e^{-28k} can be written as e^{-14k}.e^{-14k}

152=190-Ae^{-14k}.e^{14k}

Replacing (I) in the previous equation:

152=190-76e^{-14k}

Solving for k:

Subtracting 190 both sides, dividing by -76:

0.5=e^{-14k}

Applying the base e logarithm both sides:

Ln(0.5)= -14k

Dividing by -14:

k= -Ln(0.5)/14

Replacing k in (I) and solving for A:

Ae^{-14(-Ln(0.5)/14)}=76\\Ae^{Ln(0.5)} =76\\A(0.5)=76

Dividing by 0.5

A=152

7 0
3 years ago
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