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Harrizon [31]
3 years ago
13

The surface area of an oil spill gets 131% larger every day, represented by the function s(x) = (1.31)x − 1. On the first day, i

t covered an area of 21 square meters. Which function would be used to find the area of the oil spill on the 47th day?
Mathematics
1 answer:
scoray [572]3 years ago
6 0

Answer:

The correct option is B.

Step-by-step explanation:

It is given that the surface area of an oil spill gets 131% larger every day, represented by the function

Where x is number of days.

On the first day, it covered an area of 21 square meters. It means the initial area is 21 square meters.

The function is defined as

Where is initial value and b is growth factor.

It means the function of new area is the product of initial area and increasing area function. The required function is

Therefore option B is correct.

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Consider the following operations on the number 8.82 x 10^-2. Without using a calculator, decide which would give a significantl
Ksenya-84 [330]

Correct question is;

Consider the following operations on the number 8.85 x 10^(-2). Without using a calculator, decide which would give a significantly smaller value than 8.85 x 10^(-2), which would give a significantly larger value, or which would give essentially the same value.

A) 8.85 × 10^(-2) + 6.69 × 10^(5)

B) 8.85 x 10^(-2) - 6.69 x 10^(5)

C) 8.85 x 10^(-2) x 6.69 x 10^(5)

D) 8.85 × 10^(-2) ÷ 6.69 × 10^(5)

Answer:

Option A & B yield essentially the same value.

Option C yields a significantly smaller value

Option D yields a significantly larger value

Step-by-step explanation:

Since given value for the operations is in 10^(-2) indices, then let's convert the operations numbers from 10^(5) indices to 10^(-2).

Thus;

6.69 × 10^(5) = (6.69 × 10^(-7)) × 10^(-2)

Thus;

A) 8.85 × 10^(-2) + 6.69 × 10^(5) is now;

8.85 × 10^(-2) + ((6.69 × 10^(-7)) × 10^(-2))

This gives;

[8.85 + (6.69 × 10^(-7))] × 10^(-2)

The 10^(-7) indices indicates that the initial value of 8.85 × 10^(-2) would not change much and would essentially be the same

B) 8.85 x 10^(-2) - 6.69 x 10^(5) is now;

8.85 × 10^(-2) - ((6.69 × 10^(-7)) × 10^(-2))

This gives;

[8.85 - (6.69 × 10^(-7))] × 10^(-2)

Again the 10^(-7) indices indicates that the initial value of 8.85 × 10^(-2) would not change much and would essentially be the same.

C) 8.85 x 10^(-2) x 6.69 x 10^(5) is now;

(8.85 × 10^(-2)) × ((6.69 × 10^(-7)) × 10^(-2))

This gives;

[8.85 × (6.69 × 10^(-7))] × 10^(-2)

When we multiply 8.85 by 6.69 × 10^(-7), the value gotten will be way lower than the initial value of 8.85.

Thus,this operation will give a significantly smaller value.

D) (8.85 × 10-2) ÷ (6.69 × 10^5) is now;

(8.85 × 10^(-2)) ÷ ((6.69 × 10^(-7)) × 10^(-2))

This gives;

[8.85 ÷ (6.69 × 10^(-7))] × 10^(-2)

When we carry out the operation:

8.85 ÷ (6.69 × 10^(-7)), it is essentially equal to (8.85 × 10^(7))/6.69.

This means that the new value would be significantly larger than the initial value of 8.85.

Thus,this operation yields a significantly larger value.

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3 years ago
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(6, 7) and (-3, -2)

1. Find the slope.

m = slope

m = (-2 -7)/(-3 -6)

m = -9/-9

m = 1

2. Plug the slope and one of the points into the equation y - y_1 = m(x - x_1).

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3. Solve for y.

y - 7 = x - 6

y = x - 6 + 7

y = x + 1

Answer is choice D.

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3 years ago
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