There's some unknown (but derivable) system of equations being modeled by the two lines in the given graph. (But we don't care what equations make up these lines.)
There's no solution to this particular system because the two lines are parallel.
How do we know they're parallel? Parallel lines have the same slope, and we can easily calculate the slope of these lines.
The line on the left passes through the points (-1, 0) and (0, -2), so it has slope
(-2 - 0)/(0 - (-1)) = -2/1 = -2
The line on the right passes through (0, 2) and (1, 0), so its slope is
(0 - 2)/(1 - 0) = -2/1 = -2
The slopes are equal, so the lines are parallel.
Why does this mean there is no solution? Graphically, a solution to the system is represented by an intersection of the lines. Parallel lines never intersect, so there is no solution.
Answer:
Step-by-step explanation:
<u><em>The correct question is</em></u>
what is the equation for a line passing through (-2,3) and perpendicular to y= -1/2<em>x</em>+1 ?
Remember
If two lines are perpendicular, then their slopes are opposite reciprocal (the product of their slopes are equal to -1)
The slope of the given line is m=-1/2
so
the opposite reciprocal is m=2
<em>Find the equation of the line in point slope form</em>
we have
substitute
<em>Convert to slope intercept form</em>
isolate the variable y
7+5(p-p)=7
because 7+5p-5p=7
cross our the 5p because 5p-5p is 0
7=7
~JZ
Hope it helps!
Answer:
C) As x approaches positive infinity, f(x) approaches positive infinity
Step-by-step explanation:
- The domain is NOT all real numbers as x is either smaller than or bigger than 0, and smaller than or bigger than 2. So x ≠ 0 and x ≠ 2.
- This implies that there are asymptotes at x=0 and x=2.
Therefore, the function is NOT continuous.
- The function is NOT increasing over its entire domain as
f(x) = -x² -4x + 1 is decreasing for its given domain of 0<x<2
Answer:
8 square units
Step-by-step explanation:
x + 1 = 0
x = -1
x + 8 = 0
x = -8
Area = (-1) * (-8) = 8 square units
