Unfortunately there isn't enough information.
Check out the diagram below. We have segment BC equal to 120 meters long. Points B, C, D and E are all on the edge of the same circle. According to the inscribed angle theorem, angles BDC and BEC are congruent. This shows that the surveyor could be at points D or E, or the surveyor could be anywhere on the circle. There are infinitely many locations for the surveyor to be at, which leads to infinitely many possible widths of this canal.
Answer:
I believe the second one is d
Answer:
60 feet^3
Step-by-step explanation:
like you draw, cut it to two part.
the small one:
1 x 3 x 4=12 feet^3
The big one:
2 x 6 x 4=48 feet^3
So the total is:
12+48=60 feet^3
Hope it helps.
Answer:
The answer is six
Step-by-step explanation:
12 3/5 = 63/5
2 1/10 = 21/10
63/5 divided by 21/10 is equal to 63/5 multiplied by 10/21 which is equal to 630/105 = 6 <-- answer
The answer to the question