Treat this like a slope formula. Y2-y1 divided by x2-x1.
Your y2 value is the second population
Y1= value of first population.
X2= second year they give
X1= first year they give.
4700-3650
_________
2014-2012

1050
____
2

525 is the increase a year

8 0

2 years ago

When commercial aircraft are inspected, wing cracks are reported as nonexistent, detectable, or critical. The history of a parti

Kamila [148]

Answer:

0.226

Step-by-step explanation:

Given that:

No wing crack (x) = 70%

Detectable wing crack (y) = 25%

Critical wing crack (z) = 5%

Number of samples (n) = 5

Probability that atleast a plane has critical crack:

1 - p(no critical crack)

Using the multinomial distribution calculator :

P(5,0,0) + p(4,1,0) + p(3,2, 0) + p(2,3,0) + p(1,4,0) + p(0,5,0)

From the calculator :

P(5,0,0) + p(4,1,0) + p(3,2, 0) + p(2,3,0) + p(1,4,0) + p(0,5,0) = 0.7741

1 - 0.7741 = 0.2259

= 0.226

7 0

3 years ago