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3 years ago

Find the distance between (6,4) and (0,-5)

Mathematics

1 answer:

sergejj [24]3 years ago

4 0

Step-by-step explanation:

we know,

distance = √(x_2 - x_1)² + (y_2 - y_1)²

given points

(6,4) and (0,-5)

according to formula

→ d = √(0 - 6)² + (-5 - 4)²

→ √(-6)² + (-9)²

→ √36 + 81

→ √117 = 10.81 (approx.)

therefore, distance between both the points are 10.81 (approx.).

Hope this helps you !

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What is the number product of its prime factor 48

Vanyuwa [196]

The factor of 48 are : 1,2,3,4,6,8,12,16,24,48
The prime factor are : 2x2x2x2x3

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3 years ago

13. Evaluate for a = -6 and b = -2. Find ab.

Vika [28.1K]

Solution:

Given;

$a=-6,b=-2$ $ab=-6\times-2$ $ab=12$

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1 year ago

Abdi's bowling scores for June were 117, 98, 104, 121, 105, 104, 120, and 111. What is the mean of this data?

elena-s [515]

The first thing that you have to do is line it up from least to greatest: 98,104,104,105,111,117,120,121. Then you add all of the numbers and divide the total of all the number of scores she has. 880/8=110. 110 is the answer of your question. ( I got 8 because I had to count all the numbers and I got 880 because I added all the numbers).

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3 years ago

ABC ≃DEF. Find the lengths of the given sides

GuDViN [60]

Answer:

BC = 8 and EF = 8.

Step-by-step explanation:

Since triangle ABC and DEF are congruent to each other, BC corresponds with EF (as determined by the triangle names).

Set BC and EF equal to each other.

x + 6 = 3x + 2

Subtract x from both sides.

6 = 2x + 2

Subtract 2 from both sides.

4 = 2x.

Divide 2 on both sides.

x = 2.

Substitute 2 for x.

BC = 2 + 6

BC = 8

Since we already know that EF is congruent to BC, EF is also 8.

EC = 3(2) + 2

EC = 6 + 2

EC = 8

5 0

3 years ago

A researcher is going to estimate the average typing speed of students of a college. He selects a random sample of 20 students a

Stella [2.4K]

Answer:

The margin of error of the 90% confidence interval of a student's average typing speed is of 1.933 wpm.

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 20 - 1 = 19

90% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 19 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.9}{2} = 0.95$ . So we have T = 1.7291

The margin of error is:

$M = T\frac{s}{\sqrt{n}}$

In which s is the standard deviation of the sample and n is the size of the sample. For this question, we have $s = 5, n = 20$ . So

$M = T\frac{s}{\sqrt{n}}$

$M = 1.7291\frac{5}{\sqrt{20}}$

$M = 1.933$

The margin of error of the 90% confidence interval of a student's average typing speed is of 1.933 wpm.

8 0

3 years ago