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denis23 [38]
3 years ago
13

I just need help with this

Mathematics
1 answer:
ella [17]3 years ago
8 0

The formula for area of a circle is: πr^2

r is half the diameter.

FE is the diameter: r = 20/2 = 10

Area of circle using FE = π10^2 = π * 100 = 314 square meters.

BE is a radius:

Area = π3.5^2 = π * 12.25 = 38.465  = 38.5 square cm ( rounded to nearest tenth).

AB is a radius:

Area = π11^2 = π * 121 = 379.94 = 380 square feet ( rounded off).

EF is a diameter

r = 12/2 = 6 meters

Area = π6^2 = π * 36 = 113.04 = 113 square meters ( rounded off).

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Marta_Voda [28]

Answer:

  • n < 9 or n = (-oo, 9)

Step-by-step explanation:

  • -2n +7 > -11
  • -2n > -11 - 7
  • -2n > -18
  • n < -18/-2
  • n < 9
  • n = (-oo, 9)
5 0
2 years ago
What is the area of the figure?
Novay_Z [31]

Answer:

267 in. squared

Step-by-step explanation:

11 * 17 = 187 in.

10 * 8 = 80 in.

187 + 80 = 267 in.

3 0
3 years ago
Read 2 more answers
option 1 drop down are: even-odd identity, quotient identity, Pythagorean identity, double-number identity.option 2 drop down ar
motikmotik

Answer:

The equation is given below as

\frac{\cos2x}{\cos x}=\cos x-\sin x\tan x

Step 1:

We will work on the left-hand side, we will have

\begin{gathered} \cos x-\sin x\tan x \\ \text{recall that,} \\ Quoitent\text{ identity is} \\ \tan x=\frac{\sin x}{\cos x} \end{gathered}

By substituting the identity above, we will have

\begin{gathered} \cos x-\sin x\tan x=\cos x-\frac{\sin x.\sin x}{\cos x}=\cos x-\frac{\sin^2x}{\cos x} \\  \end{gathered}

Here, we will make use of the quotient identity

Step 2:

By writings an expression, we will have

\begin{gathered} \cos x-\sin x\tan x=\cos x-\frac{\sin x.\sin x}{\cos x} \\ \cos x-\sin x\tan x=\frac{\cos^2x-\sin^2x}{\cos x} \end{gathered}

Here, we will use the definition of subtraction

\cos x-\frac{\sin^2x}{\cos x}

Step 3:

We will apply the double number identity given below

\begin{gathered} \cos 2\theta=\cos (\theta+\theta)=\cos ^2\theta-\sin ^2\theta \\ \cos 2x=cos(x+x)=\cos ^2x-\sin ^2x \end{gathered}

By applying this, we will have

\frac{\cos^2x-\sin^2x}{\cos x}=\frac{\cos2x}{\cos x}

Here, we will use the double number identity

\frac{\cos^2x-\sin^2x}{\cos x}

5 0
1 year ago
Please help me its due in 3 minutes please no links I just need the answer please.
djyliett [7]

Answer:

The answer is .9.

Step-by-step explanation:

Steps Ex. 1 Ex. 2

Round a number to the nearest tenth 3.14 .883

Find the hundredths' place. 3.14 .883

Less than 5, round the tenth down. 3.1

If it is 5 or more, round the tenth up.  .9

That is your explanation. The answer is .9

6 0
2 years ago
Read 2 more answers
-17π/3<br> Find the exact values of all six trig functions
Tpy6a [65]
The six trigonometric functions are sine, cosine, tangent, cotangent, secant and cosecant. This is a first quadrant angle. sine of -17 pi over 3 is equal to square root of 3 over 2, cosine of -17 pi over 3 is equal to 1/2. tan -17 pi over 3  is equal to square root of 3. cosecant-17 pi over 3  is equal to 2/sqrt3, secant  of -17 pi over 3 is 2 while cotangent -17 pi over 3  is equal to 1/sqrt 3
3 0
3 years ago
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