Answer:
h(0)= -7
Step-by-step explanation:
that is my answer
Answer:
5.44 cm³
Step-by-step explanation:
The volume of the hexagonal nut can be found by multiplying the area of the end face by the length of the nut. The end face area is the difference between the area of the hexagon and the area of the hole.
The area of a hexagon with side length s is given by ...
A = (3/2)√3·s²
For s=1 cm, the area is ...
A = (3/2)√3(1 cm)² = (3/2)√3 cm²
__
The area of a circle is given by ...
A = πr²
The radius of a circle with diameter 1 cm is 0.5 cm. Then the area of the hole is ...
A = π(0.5 cm)² = 0.25π cm²
__
The volume is the face area multiplied by the length, so is ...
V = Bh = ((3/2)√3 -0.25π)(3) . . . . . cm³
V = (9/2)√3 -0.75π cm³ ≈ 5.44 cm³
The volume of the metal is about 5.44 cm³.
The solution to that equation is (6,-4)
Answer:
Side length = 
cm , Height = 
cm , Volume = 
cm³
Step-by-step explanation:
Assume
Side length of base = x
Height of box = y
total material required to construct box = A ( given in question)
So it can be written as
A = x² + 4xy
4xy = A - x²
Volume of box = Area x height
V = x² ₓ y
V = x² ₓ ( 
)
V = 
To find max volume put V' = 0
So taking derivative equation becomes
A = 3 
= 
x = 
put value of x in equation 1
y = 
y = 
y =
So the volume will be
V = × y
Put values of x and y from equation 2 & 3
V = 
V =
Answer:
257
Step-by-step explanation:
5(41-(-2))+{-7(-4-2)}
5(41+2)+{-7(-6)}
5(43)+(42)
215+42
257
