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poizon [28]
3 years ago
14

GEOMETRY: PLEASE HELP!!

Mathematics
1 answer:
Aloiza [94]3 years ago
7 0

Answer:

GF=72

Step-by-step explanation:

All triangles in the given figure are similar, from SAS. Notice that marked in the diagram, CD=DE=EF=FA.

For triangle \triangle CGF was base GF, leg CF contains three of these marked segments. In triangle \triangle CHE with base HE, leg CE has two of these marked segments. By definition, similar polygons have corresponding sides in a constant proportion. Therefore, the length of GF must be 3/2 the length of EH. Since the length of EH is given as 48, we have:

GF=\frac{3}{2}EH, \\\\GF=\frac{3}{2}\cdot 48,\\\\GF=\boxed{72}

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Option C:

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