Hey there!
What I would do to solve this problem is list out all four of the numbers, then place the other three numbers behind it, like so:
71
73
79
17
13
19
37
31
39
97
91
93
These are all of your possible combinations without any repeats. There's a total of 12 possible combos.
Hope this helped you out! :-)
<span>3(x + 5) = 2(3x + 18)
Use the distributive property:
3(x)+5(3)=2(3x)+18(2)
Simplify:
3x+15=6x+36
6x+36=3x+15
3x+36=15
3x=-21
x=-7
Check answer:
3(-7+5)=2(-21+18)
3(-2)=2(-3)
-6=-6
Hope this helps :)
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Answer:
the probability of having a widow peak and attached earlobe = 0.6667*0.66667 = 0.4445 = 44.5%
Step-by-step explanation:
Martha = widow's peak + attached earlobes.
Martha's dad = straight hairline + unattached earlobes.
Martha husband =straight hairline+ widow's peak + attached earlobes
what is the probability that Martha child will have a widow's peak + attached earlobes?
since,
Martha + Martha husband =straight hairline+ widow's peak + attached earlobes
the probability of the child having widow peak is 2/3 = 0.6667
the probability of the child having attached earlobes is 2/3 = 0.66667
the probability of having both = 0.6667*0.66667 = 0.4445
Hello,
answer D (-2,3)
Indeed
y=4x+11
y=-2x-1
==>4x+11=-2x-1
==>6x=-12
==>x=-2
And y=4*(-2)+11=3
The correct answer is the second one I think
g + 5 > 12; g > 7
